Chapter 18: Problem 1
In an electrochemical cell, (a) potential energy decreases (b) kinetic energy decreases (c) potential energy changes into electrical energy (d) chemical energy changes into electrical energy.
Chapter 18: Problem 1
In an electrochemical cell, (a) potential energy decreases (b) kinetic energy decreases (c) potential energy changes into electrical energy (d) chemical energy changes into electrical energy.
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Get started for freeFor a cell reaction involving \(2 e^{-}\) change, the standard emf of the cell is found to be \(0.295\) \(\mathrm{V}\) at \(25^{\circ} \mathrm{C}\). The equilibrium constant of the reaction will be (a) \(2.95 \times 10^{2}\) (b) 10 (c) \(1 \times 10^{10}\) (d) \(1 \times 10^{-10}\)
Cell reaction is spontaneous when (a) \(E_{\text {red }}^{\circ}\) is +ve (b) \(\Delta G^{\circ}\) is -ve (c) \(\Delta G^{\circ}\) is +ve (d) \(E_{\text {red }}^{\circ}\) is +ve
If the standard electrode potential of \(\mathrm{Cu}^{2}+/ \mathrm{Cu}\) electrode is \(0.34 \mathrm{~V}\), what is the electrode potential of \(0.01 \mathrm{M}\) concentration of \(\mathrm{Cu}^{2+}(T=298 \mathrm{~K}) ?\) (a) \(0.399 \mathrm{~V}\) (b) \(0.281 \mathrm{~V}\) (c) \(0.222 \mathrm{~V}\) (d) \(0.176 \mathrm{~V}\)
Saturated solution of \(\mathrm{KNO}_{3}\) is used to make a 'salt bridge' because (a) velocity of \(\mathrm{K}^{+}\) is greater than that of \(\mathrm{NO}^{-}{ }_{3}\) (b) velocity of \(\mathrm{NO}_{3}^{-}{ }_{3}\) is greater than that of \(\mathrm{K}^{+}\) (c) velocities of \(\mathrm{K}^{+}\) and \(\mathrm{NO}^{-}{ }_{3}\) both are nearly the same (d) none of the above
The oxidation potential of \(\mathrm{Mg}\) and \(\mathrm{Al}\) are \(+2.37\) and \(+1.66\) volts respectively. The \(\mathrm{Mg}\) in the chemical reaction (a) will be replaced by Al (b) will replace \(\mathrm{Al}\) (c) will not be able to replace \(\mathrm{Al}\) (d) none of the above
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