Chapter 18: Problem 6
In the electrochemical cell, flow of electrons is from (a) cathode to anode in the solution (b) cathode to anode through external supply (c) cathode to anode through internal supply (d) anode to cathode through internal supply
Chapter 18: Problem 6
In the electrochemical cell, flow of electrons is from (a) cathode to anode in the solution (b) cathode to anode through external supply (c) cathode to anode through internal supply (d) anode to cathode through internal supply
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Get started for freeSaturated solution of \(\mathrm{KNO}_{3}\) is used to make a 'salt bridge' because (a) velocity of \(\mathrm{K}^{+}\) is greater than that of \(\mathrm{NO}^{-}{ }_{3}\) (b) velocity of \(\mathrm{NO}_{3}^{-}{ }_{3}\) is greater than that of \(\mathrm{K}^{+}\) (c) velocities of \(\mathrm{K}^{+}\) and \(\mathrm{NO}^{-}{ }_{3}\) both are nearly the same (d) none of the above
Three elements \(A, B\) and \(C\) have reduction potentials \(-1.5,-0.05\), and \(+1.50\). Then the correct order of their reducing power is (a) \(A>B>C\) (b) \(B>A>C\) (c) \(C>B>A\) (d) \(B>C>A\)
Cell reaction is spontaneous when (a) \(E_{\text {red }}^{\circ}\) is +ve (b) \(\Delta G^{\circ}\) is -ve (c) \(\Delta G^{\circ}\) is +ve (d) \(E_{\text {red }}^{\circ}\) is +ve
For the overall reaction $$ \mathrm{Cu}^{2+}\left(\mathrm{C}_{1} \mathrm{aq}\right)+\mathrm{Zn}(\mathrm{s}) \rightarrow \mathrm{Zn}^{2+}\left(C_{2} \mathrm{aq}\right)+\mathrm{Cu}(\mathrm{s}) $$ (a) \(\ln C_{1}\) (b) \(\ln \left(C_{2} / C_{1}\right)\) (c) \(\ln C_{2}\) (d) \(\ln \left(C_{1}+C_{2}\right)\) of an electrochemical cell, the change in the free energy \(\Delta G\) at a given temperature is a function of (a) \(\ln C_{1}\) (b) \(\ln \left(C_{2} / C_{1}\right)\) (c) \(\ln C_{2}\) (d) \(\ln \left(C_{1}+C_{2}\right)\)
For a cell reaction involving \(2 e^{-}\) change, the standard emf of the cell is found to be \(0.295\) \(\mathrm{V}\) at \(25^{\circ} \mathrm{C}\). The equilibrium constant of the reaction will be (a) \(2.95 \times 10^{2}\) (b) 10 (c) \(1 \times 10^{10}\) (d) \(1 \times 10^{-10}\)
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