Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 28: Problem 3

\({ }_{14}^{30} \mathrm{Si},{ }_{15}^{31} \mathbf{p}\) and \({ }_{16}^{32} \mathrm{~S}^{a r e}\) (a) isotopes (b) isobars (c) isotones (d) none of these

Short Answer

Expert verified
The atomic structures \({ }_{14}^{30} \mathrm{Si},{ }_{15}^{31} \mathrm{P}\) and \( { }_{16}^{32} \mathrm{S}\) are isotones, having the same number of neutrons.

Step by step solution

01

Identify each atom's atomic number and mass number

The subscript (lower number) is the atomic number (Z), which is the number of protons. The superscript (upper number) is the mass number (A), which is the number of protons plus neutrons. Let's determine them for each atom. For \({ }_{14}^{30} \mathrm{Si}\), Z=14 and A=30; for \({ }_{15}^{31} \mathrm{P}\), Z=15 and A=31; for \({ }_{16}^{32} \mathrm{S}\), Z=16 and A=32. So, the number of neutrons (N) is A-Z. Therefore, for \({ }_{14}^{30} \mathrm{Si}\), N=30-14=16; for \({ }_{15}^{31} \mathrm{P}\), N=31-15=16; and for \({ }_{16}^{32} \mathrm{S}\), N=32-16=16.
02

Classify the atoms

As they do not have the same atomic nor mass numbers, they cannot be classified as isotopes nor isobars. However, they all have the same neutron number (16), so they can be classified as isotones.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which of the following is not a method of detection and measurement of radioactivity? (a) Slater method (b) Wilson cloud chamber method (c) Geiger-Muller counter (d) Scintillation method

The reaction \({ }_{1}^{1} \mathrm{H}+{ }_{1}^{1} \mathrm{H}+2{ }_{0}^{1} \mathrm{n} \longrightarrow{ }_{2}^{4} \mathrm{He}^{+}\) Energy is an example if (a) capture reaction (b) spallation reaction (c) fusion reaction (d) fission reaction

Isotopes are atom having the (a) same atomic number but different atomic masses (b) different atomic numbers but same atomic mass (c) same atomic number and atomic mass (d) different atomic numbers and atomic masses

The stable end product in the uranium series \(\left({ }_{92}^{238} \mathrm{U}\right)\) is (a) \({ }_{82}^{205} \mathrm{~Pb}\) (b) \({ }_{82}^{206} \mathrm{~Pb}\) (c) \({ }_{82}^{207} \mathrm{~Pb}\) (d) \({ }_{82}^{208} \mathrm{~Pb}\)

Magic numbers as applied to stability of atom are (a) \(1,7,19,27\) (b) \(3,9,21,29\) (c) \(10,20,30,40\) (d) \(2,8,20,28\)
See all solutions

Recommended explanations on Chemistry Textbooks

Chemical Reactions

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Chemistry Branches

Read Explanation

Making Measurements

Read Explanation

Inorganic Chemistry

Read Explanation

Physical Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free