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Chapter 3: Problem 4

The gas that is heated up during Joule-Thomson effect at ordinary temperature is: (a) \(\mathrm{O}_{2}\) (b) \(\mathrm{CO}_{2}\) (c) \(\mathrm{H}_{2}\) (d) \(\mathrm{SO}_{2}\)

Short Answer

Expert verified
The gas that heats up during the Joule-Thomson effect at normal temperature is Hydrogen (\(\mathrm{H}_{2}\)).

Step by step solution

01

Understanding the Joule-Thomson effect

Recognize that the Joule-Thomson effect states that gases cool upon expansion, but Hydrogen and Helium heat up under normal conditions. This means that for the mentioned gases, when they expand, their temperature will increase.
02

Identifying the correct gas

Look at the given options. The gases given are Oxygen (\(\mathrm{O}_{2}\)), Carbon Dioxide (\(\mathrm{CO}_{2}\)), Hydrogen (\(\mathrm{H}_{2}\)), and Sulfur Dioxide (\(\mathrm{SO}_{2}\)). Among these, Hydrogen (\(\mathrm{H}_{2}\)) is the gas that would heat up when expanded under normal conditions according to the Joule-Thomson effect.

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Most popular questions from this chapter

Gases deviate from the ideal gas behaviour because their molecules (a) possess negligible volume (b) have forces of attraction between them (c) are polyatomic (d) are not attracted to one another

The gas which can be liquefied under high pressure and \(40^{\circ} \mathrm{C}\) is (a) nitrogen (b) hydrogen (c) oxygen (d) ammonia

The temperature at which the second virial coefficient of a real gas is zero is called: (a) critical temperature (b) eutactic point (c) boiling point (d) Boyle's temperature

An ideal gas cannot be liquefied because (a) its critical temperature is always above \(0^{\circ} \mathrm{C}\) (b) its molecules are relatively smaller or in size (c) it solidifies before becoming a liquid (d) forces operative between its molecules are negligible

Critical temperature means above this temperature at any pressure, any gas can be (a) liquefied (b) not liquefied (c) both statements are correct (d) Solified
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