Chapter 3: Problem 6
The van der Waals equation explains the behaviour of (a) ideal gas (b) real gases (c) vapours (d) non-real gases
Chapter 3: Problem 6
The van der Waals equation explains the behaviour of (a) ideal gas (b) real gases (c) vapours (d) non-real gases
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Get started for freeAn ideal gas cannot be liquefied because (a) its critical temperature is always above \(0^{\circ} \mathrm{C}\) (b) its molecules are relatively smaller or in size (c) it solidifies before becoming a liquid (d) forces operative between its molecules are negligible
According to the van der Waals correction to get the pressure of ideal gas in observed pressure a definite fraction for correction is (a) subtracted (b) added (c) divided (d) unchanged
The gas which can be liquefied under high pressure and \(40^{\circ} \mathrm{C}\) is (a) nitrogen (b) hydrogen (c) oxygen (d) ammonia
Which one of the following gases has the maximum value of root mean square velocity? (a) \(\mathrm{CH}_{4}\) (b) \(\mathrm{CO}_{2}\) (c) \(\mathrm{H}_{2}\) (d) \(\mathrm{CO}\)
An ideal gas, obeying kinetic theory of gases, can be liquefied: (a) It cannot be liquefied at any \(P\) and \(T\) (b) Its pressure is more than \(P\) at a temperature less than \(T\) (c) Its temperature is more than critical temperature \(T\) (d) Its pressure is more than critical pressure \(P\)
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