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Chapter 3: Problem 9

Expansion of a gas above inversion temperature creates (a) cooling (b) heating (c) constant temperature (d) none

Short Answer

Expert verified
The correct option is (b) heating

Step by step solution

01

Understand the concept of inversion temperature

Inversion temperature is a concept in thermodynamics and it's the temperature at which a gas changes from being cooler upon expansion to being warmer. Above the inversion temperature, if the system (gas) expands, it gets warmer. So, comprehend thoroughly the idea of inversion temperature.
02

Apply the understanding to the question

Looking at the question, we need to identify what happens to gas when it expands above its inversion temperature. Based on the understanding from Step 1, when a gas expands above its inversion temperature, it gets warmer or experiences heating.

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Most popular questions from this chapter

A gas is said to behave like an ideal gas when the relation \(P V / T=\) constant. When do you expect a real gas to behave like an ideal gas? (a) When the temperature is low (b) When both the temperature and pressure are low (c) When both the temperature and pressure are high (d) When the temperature is high and pressure is low

The value of \(C_{p} / C_{v}\) for inert gases is (a) \(1.33\) (b) \(1.66\) (c) \(2.13\) (d) \(1.99\)

Critical temperature means above this temperature at any pressure, any gas can be (a) liquefied (b) not liquefied (c) both statements are correct (d) Solified

A real gas will approach the behaviour of ideal gas at (a) low temperature and low pressure (b) low temperature and high pressure (c) high temperature and high pressure (d) high temperature and low temperature

Which set of conditions represent easiest way to liquefy a gas? (a) Low temperature and high pressure (b) High temperature and low pressure (c) Low temperature and low pressure (d) High temperature and high pressure
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