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Chapter 5: Problem 16

In a unit cell of \(\mathrm{NaCl}\) lattice there are: (a) \(4 \mathrm{NaCl}\) units (b) \(3 \mathrm{Na}^{+}\) ions (c) \(6 \mathrm{Na}^{+}\) ions (d) \(6 \mathrm{Cl}^{-}\) ions

Short Answer

Expert verified
The correct answers are (a) 4 NaCl units, there are neither (b) 3 Na+ ions, nor (c) 6 Na+ ions in a unit cell. Also, there are not (d) 6 Cl- ions in a unit cell.

Step by step solution

01

Understand the NaCl unit cell structure

Sodium Chloride (NaCl) has a face-centered cubic unit cell structure. In this structure, every sodium ion (Na+) is surrounded by six chloride ions (Cl-) and similarly, every chloride ion is surrounded by six sodium ions. This means that one unit cell of NaCl will have 4 NaCl units.
02

Count the Na+ ions

As explained in previous step, in one unit cell of NaCl, each unit of NaCl contains one Na+ ion. Hence, in 4 NaCl units, there would be 4 Na+ ions.
03

Count the Cl- ions

Similarly, as explained, in one unit cell of NaCl, each unit of NaCl contains one Cl- ion. Hence, in 4 NaCl units, there would be 4 Cl- ions.

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Most popular questions from this chapter

Interplanar distances in crystal can be determined by equation (a) \(n \lambda=2 d \sin \theta\) (b) \(n=\lambda d \sin \theta\) (c) \(\frac{n}{\lambda}=2 d \sin \theta\)

Axis of symmetry in crystals is given by the general formula (a) \(\frac{360^{\circ}}{n}\) (b) \(n \times 360^{\circ}\) (c) \(n \times 180^{\circ}\) (d) \(n / 90^{\circ}\)

If a plane is parallel to an axis of crystal its Miller index will be: (a) zero (b) infinity (c) one (d) none

In Bragg's equation for diffraction of X-rays, \(n\) represents a) number of moles b) quantum number c) order of reflection d) Avogadro number

Radius ratio \(r_{\mathrm{Na}}+/ r_{\mathrm{C} 1}^{-}\) in \(\mathrm{NaCl}\) crystal is a) \(0.524\) b) \(0.414\) c) \(0.732\) d) \(0.80\)
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