For the chemical change \(A \rightarrow B\), it is found that the rate reaction doubles when the concentration is increased four times. The order in \(A\) for this reaction is (a) two (b) one (c) zero (d) half

Short Answer

Expert verified
The order of the reaction with respect to \(A\) is half.

Step by step solution

01

Understand the Rate Law

The rate law provides a mathematical relationship between the rate of a reaction and the concentration of the reactants. It typically has the form rate = \(k[A]^n\), where \(k\) is the rate constant, \(A\) represents the concentration of reactant \(A\), and \(n\) is the order of the reaction with respect to \(A\). The order of the reaction tells us how changing the concentration of \(A\) will affect the rate of reaction. It is determined experimentally.
02

Analyze the Given Information

In this question, we're told that the rate of reaction doubles - that is, it increases by a factor of 2 - when the concentration of \(A\) is increased four times. Thus, we can set up the equation \(2 = 4^n\), where \(n\) is the order of the reaction we're trying to find.
03

Solve the Equation for n

Solving the equation \(2 = 4^n\) for \(n\) gives the order of the reaction. Since \(4^0.5 = 2\), it can be determined that \(n = 0.5\).

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