The one which is a unimolecular reaction is (a) \(2 \mathrm{HI} \rightarrow \mathrm{H}_{2}+\mathrm{I}_{2}\) (b) \(\mathrm{N}_{2} \mathrm{O}_{5} \rightarrow \mathrm{N}_{2} \mathrm{O}_{5}+(1 / 2) \mathrm{O}_{2}\) (c) \(\mathrm{H}_{2}+\mathrm{Cl}_{2} \rightarrow 2 \mathrm{HCl}\) (d) \(\mathrm{PCl}_{3}+\mathrm{Cl}_{2} \rightarrow \mathrm{PCl}_{5}\)

Short Answer

Expert verified
None of the options represents a unimolecular reaction.

Step by step solution

01

Analyze the given reactions

In this step, we analyze each of the given reactions by looking at the reactant side and count the number of molecules involved in the reaction. \n(a) \(2 HI \rightarrow H_{2}+I_{2}\): In this reaction, 2 molecules of Hydrogen Iodide are reacting. So, it's not unimolecular.\n(b) \(N_{2}O_{5} \rightarrow N_{2}O_{5}+(1 / 2)O_{2}\): This is incorrect. Reaction has the same molecule on both sides which is a mistake. \n(c) \(H_{2}+Cl_{2} \rightarrow 2 HCl\): Here, Hydrogen and Chlorine molecules are involved, so it's not unimolecular either.\n(d) \(PCl_{3}+Cl_{2} \rightarrow PCl_{5}\): In this reaction, two molecules, i.e., Phosphorus Trichloride and Chlorine are reacting. Hence, it's not unimolecular.
02

Final analysis and short answer

On analyzing all the options, it is seen that none of the reactions given in the options are unimolecular reactions. Therefore, none of the reactions mentioned in the question is unimolecular.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free