Concerns over the harmful effects of chlorofluorocarbons on stratospheric ozone have motivated a search for new refrigerants. One such alternative is 2,2 -dichloro-1,1,1-trifluoroethane (refrigerant 123). Younglove and McLinden published a compendium of thermophysical properties of this substance (B.A. Younglove and M. McLinden, \(J\). Phys. Chem. Ref Data 23,7 (1994)), from which properties such as the Joule-Thomson coetficient \(\mu\) can be computed. (a) Compute \(\mu\) at \(1.00\) bar and \(50^{\circ} \mathrm{C}\) given that \((\partial H / \partial p)_{T},=-3.29\) \(\times 10^{3} \mathrm{~J} \mathrm{MPa}^{-1} \mathrm{~mol}^{-1}\) and \(C_{p \cdot m}=110.0 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\). (b) Compute the temperature change that would accompany adiabatic expansion of \(2.0 \mathrm{~mol}\) of this refrigerant from \(1.5\) bar to \(0.5\) bar at \(50^{\circ} \mathrm{C}\).

Short Answer

Expert verified
The Joule-Thomson coefficient \(\mu = -2.99 \times 10^{-3} \text{ K/bar}\). The temperature increase for adiabatic expansion of \(2.0 \text{ mol}\) refrigerant from \(1.5\text{ bar}\) to \(0.5\text{ bar}\) at \(50^\circ\text{C}\) is approximately \(0.006\text{K}\).

Step by step solution

01

Understanding the Joule-Thomson Coefficient

The Joule-Thomson coefficient \(\mu\) measures the change in temperature of a gas or liquid when it is forced through a valve or porous plug while kept insulated so that no heat is exchanged with the environment. The value of \(\mu\) can be calculated using the formula \(\mu = \left(\frac{\partial T}{\partial P}\right)_H = \frac{\left(\frac{\partial H}{\partial P}\right)_T}{C_{p,m}}\), where \(C_{p,m}\) is the molar heat capacity at constant pressure.
02

Calculating the Joule-Thomson Coefficient

Given that \(\left(\frac{\partial H}{\partial p}\right)_T = -3.29 \times 10^3 \text{ J MPa}^{-1} \text{ mol}^{-1}\) and \(C_{p.m} = 110.0 \text{ J K}^{-1} \text{ mol}^{-1}\), we can plug these values into the formula to get \(\mu = \frac{-3.29 \times 10^3 \text{ J MPa}^{-1} \text{ mol}^{-1}}{110.0 \text{ J K}^{-1} \text{ mol}^{-1}}\). However, note that the pressure derivative is given in MPa, and we need to convert MPa to bar because \(\mu\) is typically expressed in K/bar. The conversion factor is 1 MPa = 10 bar.
03

Convert Pressure Derivative to Bars

By converting the pressure derivative from MPa to bar, we get \(\left(\frac{\partial H}{\partial p}\right)_T = -3.29 \times 10^3 \text{ J MPa}^{-1} \text{ mol}^{-1} = -3.29 \times 10^2 \text{ J bar}^{-1} \text{ mol}^{-1}\), because 1 MPa = 10 bar.
04

Completing the Joule-Thomson Coefficient Calculation

Now we can calculate \(\mu\) as \(\mu = \frac{-3.29 \times 10^2 \text{ J bar}^{-1} \text{ mol}^{-1}}{110 \text{ J K}^{-1} \text{ mol}^{-1}} = -2.99 \times 10^{-3} \text{ K/bar}\).
05

Understanding the Adiabatic Expansion Process

To compute the temperature change during adiabatic expansion, we can assume that the Joule-Thomson coefficient \(\mu\) remains constant over small pressure ranges. Thus, the change in temperature can be estimated using the relationship \(\Delta T = \mu \cdot \Delta P\), where \(\Delta P\) is the change in pressure.
06

Calculating the Temperature Change

Given the initial pressure \(P_1 = 1.5 \text{ bar}\) and the final pressure \(P_2 = 0.5 \text{ bar}\), the change in pressure is \(\Delta P = P_2 - P_1 = 0.5 \text{ bar} - 1.5 \text{ bar} = -1.0 \text{ bar}\). With the calculated \(\mu = -2.99 \times 10^{-3} \text{ K/bar}\), we find \(\Delta T = \mu \cdot \Delta P = -2.99 \times 10^{-3} \text{ K/bar} \cdot -1.0 \text{ bar} = 2.99 \times 10^{-3} \text{ K}\). Since we have \(2.0 \text{ mol}\) of refrigerant, the total change in temperature for the entire amount is \(\Delta T_{total} = \Delta T \cdot \text{mol amount} = 2.99 \times 10^{-3} \text{ K} \cdot 2.0 = 5.98 \times 10^{-3} \text{ K}\), or approximately \(0.006\text{ K}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermophysical Properties
Thermophysical properties are crucial characteristics of materials that define their behavior under various thermal conditions. They include properties such as thermal conductivity, specific heat, thermal expansion coefficient, and in the context of this discussion, the Joule-Thomson coefficient. Understanding these properties is essential for the design and operation of thermal systems, such as refrigeration units, where safety and efficiency are paramount.

In the case of refrigerant 123, a potential alternative for harmful chlorofluorocarbons, calculating its thermophysical properties allows us to understand how it will perform under certain temperature and pressure conditions. These computations are not just theoretical exercises; they are applied by engineers to predict how refrigerants will behave in real-world applications, ensuring that alternatives to harmful substances can be utilized effectively and responsibly.
Adiabatic Expansion
Adiabatic expansion is a process where a gas or liquid expands in volume without exchanging heat with its surrounding environment. This process is isenthalpic, meaning there is no change in the enthalpy (total heat content) of the system. It is a core concept in thermodynamics and plays a crucial role in refrigeration and air conditioning systems.

Understanding adiabatic expansion helps in predicting the cooling effect when a refrigerant expands within the coils of a refrigerator or air conditioning unit. During this process, the temperature of the refrigerant often drops, which is harnessed to cool the air or contents of a refrigerator. The Joule-Thomson effect, which quantifies the change in temperature during an adiabatic expansion when a real gas or liquid passes through a valve or porous plug, is critical in designing efficient cooling systems.
Molar Heat Capacity
The molar heat capacity of a substance is a measure of the amount of heat energy required to raise the temperature of one mole of the substance by one degree Celsius at constant pressure. It is denoted by the symbol \(C_{p,m}\) for constant pressure conditions. For refrigerant 123, which we study as an alternative to more harmful substances, knowing its molar heat capacity allows us to calculate how much heat it can absorb or release during phase changes or temperature fluctuations.

The molar heat capacity plays a key role in determining the efficiency of the refrigerant during the refrigeration cycle. By understanding \(C_{p,m}\), engineers can predict how well a refrigerant can carry heat from one place to another, which is essential for the cooling performance of a refrigeration system.

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Most popular questions from this chapter

Since their discovery in 1985, fullerenes have received the attention of many chemical researchers. Kolesov et al. reported the standard enthalpy of combustion and of formation of crystalline \(\mathrm{C}_{60}\) based on calorimetric measurements (V.P. Kolesov, S.M. Pimenova, V.K. Pavlovich, N.B. Tamm, and A.A. Kurskaya, \(J\). Chem. Thermodynamics \(\mathbf{2 8}, 1121(1996)\) ). In one of their runs, they found the standard specific internal energy of combustion to be \(-36.0334 \mathrm{~kJ} \mathrm{~g}^{-1}\) at \(298.15 \mathrm{~K}\) Compute \(\Delta_{\mathrm{c}} H^{\Theta}\) and \(\Delta_{\mathrm{f}} H^{\Theta}\) of \(\mathrm{C}_{60}\)

Show that the following functions have exact differentials: (a) \(x^{2} y+3 y^{2}\), (b) \(x \cos x y\), (c) \(x^{3} y^{2}\), (d) \(t\left(t+e^{3}\right)+s\).

A gas obeys the equation of state \(V_{m}=R T / p+a T^{2}\) and its constantpressure heat capacity is given by \(C_{p^{\prime} m}=A+B T+C p\), where \(a, A, B\), and Care constants independent of \(T\) and \(p .\) Obtain expressions for (a) the JouleThomson coefficient and (b) its constant-volume heat capacity.

Rearrange the van der Waals equation of state to give an expression for \(T\) as a function of \(p\) and \(V\) (with \(\mathrm{n}\) constant). Calculate \((\partial T / \partial p)_{\mathrm{v}}\), and confirm that \((\partial \mathrm{T} / \partial p)_{\mathrm{v}}=1 /(\partial p / \partial \mathrm{T})_{v}\). Go on to confirm Euler's chain relation.

Silylene \(\left(\mathrm{SiH}_{2}\right)\) is a key intermediate in the thermal decomposition of silicon hydrides such as silane \(\left(\mathrm{SiH}_{4}\right)\) and disilane \(\left(\mathrm{Si}_{2} \mathrm{H}_{6}\right)\). Moffat et al. (H.K. Moffat, K.F. Jensen, and R.W. Carr, J. Phys. Chem. 95,145 (1991)) report \(\Delta_{1} H\) \(\left.\Theta_{\mathrm{SiH}_{2}}\right)=+274 \mathrm{kl} \mathrm{mol}^{-1} .\) If \(\Delta_{1} H^{\Theta}\left(\mathrm{SiH}_{4}\right)=+34.3 \mathrm{kj} \mathrm{mol}^{-1}\) and \(\Delta_{1} H^{\mathrm{O}}\left(\mathrm{Si}_{2}, \mathrm{H}_{6}\right)\) \(=+80.3 \mathrm{kj} \mathrm{mol}^{-1}\) (CRC Handbook (2004)), compute the standard enthalpies of the following reactions: a. \(\mathrm{SiH}_{4}(\mathrm{~g}) \rightarrow \mathrm{SiH}_{2}(\mathrm{~g})+\mathrm{H}_{2}(\mathrm{~g})\) b. \(\mathrm{Si}_{2} \mathrm{H}_{6}(\mathrm{~g}) \rightarrow \mathrm{SiH}_{2}(\mathrm{~g})+\mathrm{SiH}_{4}(\mathrm{~g})\)

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