At \(200 \mathrm{~K}\), the compression factor of oxygen varies with pressure as shown below. Evaluate the fugacity of oxygen at this temperature and 100 atm. $$ \begin{array}{llllllll} \text { p/atm } & 1.0000 & 4.00000 & 7.00000 & 10.0000 & 40.00 & 70.00 & 100.0 \\\ Z & 0.9971 & 0.98796 & 0.97880 & 0.96956 & 0.8734 & 0.7764 & 0.6871 \end{array} $$

Short Answer

Expert verified
The fugacity of oxygen at 200 K and 100 atm is 68.71 atm.

Step by step solution

01

Understand Fugacity Concept

Fugacity is a measure of a gas's potential to escape or expand and it's similar to pressure. It's given by the product of the gas's pressure and its compression factor (Z) at a given temperature.
02

Collect Given Data

From the table, at 100 atm, the compression factor (Z) of oxygen is 0.6871. Temperature is given as 200 K but is not required for this calculation.
03

Calculate the Fugacity of Oxygen

Using the definition of fugacity (f), which is the product of pressure (p) and the compression factor (Z), calculate the fugacity at 100 atm. Use the formula: \( f = p \times Z \).
04

Substitute the Values into the Formula

Substitute \( p = 100 \) atm and \( Z = 0.6871 \) into the formula to get \( f = 100 \times 0.6871 \).
05

Perform the Calculation

After substitution, calculate the value of fugacity: \( f = 100 \times 0.6871 = 68.71 \) atm.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Compression Factor
In the world of physical chemistry, the compression factor, also known as the Z-factor, is a crucial property when studying the behavior of gases under varying pressures. It compares the behavior of a real gas with that of an ideal gas under the same conditions. For an ideal gas, which is a hypothetical gas that perfectly follows the gas laws, the compression factor is always 1. However, real gases deviate from this ideal behavior due to molecular interactions and the finite volume of gas molecules.

When the pressure on a gas increases, the particles get closer together, and the intermolecular forces become significant. This deviation from ideality is quantified by the compression factor. Mathematically, the compression factor is defined as the ratio of the actual molar volume of a gas to the molar volume of an ideal gas at the same temperature and pressure. It's an essential factor for refining the precision of gas-related calculations in thermodynamics.
Thermodynamics
Thermodynamics is a branch of physical science that deals with the relations between heat and other forms of energy, such as work. It describes how thermal energy is converted to other forms of energy and how it affects matter. The study of thermodynamics involves several key laws which underpin the physical behavior of systems in thermal equilibrium. These laws can be applied to a wide range of topics, from designing engines and refrigerators to predicting the behavior of weather systems and stars.

Within thermodynamics, the concept of fugacity represents an advanced way of understanding a gas's pressure, accounting for non-ideality. The four fundamental laws of thermodynamics—zeroth, first, second, and third—outline the principles of energy conservation, the direction of energy transfer, and the conditions for thermal equilibrium. Utilizing these principles, scientists and engineers can predict how a gas, such as oxygen, behaves under various temperature and pressure conditions.
Physical Chemistry
Physical chemistry is the study of how matter behaves on a molecular and atomic level and how chemical reactions occur. It is the discipline where physics and chemistry intersect and is essential for understanding the physical properties of molecules and the forces that act upon them. In physical chemistry, the behavior of gases plays a significant role, and it involves concepts such as fugacity and the compression factor.

Subjects like kinetics, quantum mechanics, and thermodynamics fall under this area of chemistry. The study of how real gases deviate from ideal gas behavior through the use of concepts such as the compression factor (Z) is a practical application of physical chemistry. Understanding these concepts helps scientists and engineers to manipulate the physical world in useful ways, from creating new materials to understanding biological systems and the environment.
Gas Laws
Gas laws are fundamental principles that predict the behavior of gases under various conditions of pressure, volume, and temperature. These laws include Boyle's law, Charles's law, Avogadro's law, and the ideal gas law. While these laws describe the relationship between these variables for ideal gases, real gases often display behaviors that diverge from these ideal predictions due to their intermolecular interactions.

The ideal gas law, which is the unification of Boyle's, Charles's, and Avogadro's laws, can be stated as PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. However, to account for non-ideal behavior, the concept of the compression factor (Z) is introduced, modifying the ideal gas equation to PV = nZRT. This improvement allows the estimation of real gas behavior under conditions where they do not act as ideal gases.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose that \(S\) is regarded as a function of \(p\) and \(\mathrm{T}\). Show that \(T \mathrm{dS}=\) \(C_{\mathrm{p}} \mathrm{d} T-\alpha T V \mathrm{~d} p .\) Hence, show that the energy transferred as heat when the pressure on an incompressible liquid or solid is increased by \(\Delta p\) is equal to \(-\alpha T V \Delta p .\) Evaluate \(q\) when the pressure acting on \(100 \mathrm{~cm}^{3}\) of mercury at \(0^{\circ} \mathrm{C}\) is increased by \(1.0\) kbar. \(\left(\alpha=1.82 \times 10^{-4} \mathrm{~K}^{-1} .\right)\)

The cycle involved in the operation of an internal combustion engine is called the Otto cycle. Air can be considered to be the working substance and can be assumed to be a perfect gas. The cycle consists of the following steps: (1) reversible adiabatic compression from \(\mathrm{A}\) to \(\mathrm{B},(2)\) reversible constantvolume pressure increase from \(\mathrm{B}\) to \(\mathrm{C}\) due to the combustion of a small amount of fuel, (3) reversible adiabatic expansion from \(\mathrm{C}\) to \(\mathrm{D}\), and \((4)\) reversible and constant-volume pressure decrease back to state A. Determine the change in entropy (of the system and of the surroundings) tor each step of the cycle and determine an expression for the efficiency of the cycle, assuming that the heat is supplied in Step \(2 .\) Evaluate the efficiency for a compression ratio of \(10: 1\). Assume that, in state \(\mathrm{A}, \mathrm{V}=4.00 \mathrm{dm}^{3}, p=1.00 \mathrm{~atm}\), and \(\mathrm{T}=300 \mathrm{~K}\), that \(\mathrm{V}_{\mathrm{A}}==10 \mathrm{~V}_{\mathrm{B}}, \mathrm{p}_{\mathrm{C}} / \mathrm{p}_{\mathrm{B}}=5\), and that \(C_{p m}=\frac{2}{2} R\).

A gaseous sample consisting of \(1.00 \mathrm{~mol}\) molecules is described by the equation of state \(p \mathrm{~V}_{\mathrm{m}}=\mathrm{RT}(1+B p)\). Initially at \(373 \mathrm{~K}\), it undergoes JouleThomson expansion from \(100 \mathrm{~atm}\) to \(1.00 \mathrm{~atm}\). Given that \(C_{p, \mathrm{~m}}=R, \mu=0.21\) \(\mathrm{K} \mathrm{atm}^{-1}, B=-0.525(\mathrm{~K} / T) \mathrm{atm}^{-1}\), and that these are constant over the temperature range involved, calculate \(\Delta T\) and \(\Delta S\) for the gas.

In biological cells, the energy released by the oxidation of foods (Impact on Biology \(12.2)\) is stored in adenosine triphosphate (ATP or \(\mathrm{ATP}^{4-}\) ). The essence of ATP's action is its ability to lose its terminal phosphate group by hydrolysis and to form adenosine diphosphate (ADP or ADP \(^{3-}\) ): $$ \mathrm{ATP}^{4-}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\mathrm{I}) \rightarrow \mathrm{ADP}^{3-}(\mathrm{aq})+\mathrm{HPO}_{4}^{2-}(\mathrm{aq})+\mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq}) $$ At \(\mathrm{pH}=7.0\) and \(37^{\circ} \mathrm{C}\) (310 \(\mathrm{K}\), blood temperature) the enthalpy and Gibbs energy of hydrolysis are \(\Delta_{\mathrm{r}} H=-20 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and \(\Delta_{\mathrm{r}} G=-31 \mathrm{~kJ} \mathrm{~mol}^{-1}\), respectively. Under these conditions, the hydrolysis of \(1 \mathrm{~mol} \Delta \mathrm{TP}^{4-}(\mathrm{aq})\) results in the extraction of up to \(31 \mathrm{~kJ}\) of energy that can be used to do nonexpansion work, such as the synthesis of proteins from amino acids, muscular contraction, and the activation of neuronal circuits in our brains. (a) Calculate and account for the sign of the entropy of hydrolysis of ATP at \(\mathrm{pH}=7.0\) and \(310 \mathrm{~K}\). (b) Suppose that the radius of a typical biological cell is \(10 \mu \mathrm{m}\) and that inside it \(10^{6}\) ATP molecules are hydrolysed each second. What is the power density of the cell in watts per cubic metre \(\left(1 \mathrm{~W}=1 \mathrm{~J} \mathrm{~S}^{-1}\right) ? \mathrm{~A}\) computer battery delivers about \(15 \mathrm{~W}\) and has a volume of \(100 \mathrm{~cm}^{3}\). Which has the greater power density, the cell or the battery? (c) The formation of glutamine from glutamate and ammonium ions requires \(14.2 \mathrm{~kJ} \mathrm{~mol}^{-1}\) of energy input. It is driven by the hydrolysis of ATP to ADP mediated by the enzyme glutamine synthetase. How many moles of ATP must be hydrolysed to form 1 mol glutamine?

To calculate the work required to lower the temperature of an object, we need to consider how the coefficient of performance changes with the temperature of the object. (a) Find an expression for the work of cooling an object from \(\mathrm{T}\), to \(\mathrm{T}_{\mathrm{r}}\) when the refrigerator is in a room at a temperature \(\mathrm{T}_{\mathrm{h}}\). Hint. Write \(d w=d y l c\left(T\right.\) relate \(d q\) to \(\mathrm{dT}\) through the heat capacity \(\mathrm{C}_{p}\), and integrate the resulting expression. Assume that the heat capacity is independent of temperature in the range of interest. (b) Use the result in part (a) to calculate the work needed to freeze \(250 \mathrm{~g}\) of water in a refrigerator at \(293 \mathrm{~K}\). How long will it take when the refrigerator operates at \(100 \mathrm{~W}\) ?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free