Chapter 4: Problem 15
In the 'gas saturation method' for the measurement of vapour pressure, a volume \(V\) of gas (as measured at a temperature \(T\) and a pressure \(\mathrm{p}\) ) is bubbled slowly through the liquid that is maintained at the temperature \(T\), and a mass loss \(m\) is measured. Show that the vapour pressure, \(p\), of the liquid is related to its molar mass, \(\mathrm{M}\), by \(p=A m P /(1+A m)\), where \(\mathrm{A}=R T / M P V\). The vapour pressure of geraniol \(\left(M=154.2 \mathrm{~g} \mathrm{~mol}^{-1}\right)\), which is a component of oil of roses, was measured at \(110^{\circ} \mathrm{C}\). It was found that, when \(5.00 \mathrm{dm}^{3}\) of nitrogen at 760 Torr was passed slowly through the heated liquid, the loss of mass was \(0.32 \mathrm{~g}\). Calculate the vapour pressure of geraniol.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.