Calculate the resolution and efficiency of two compounds. Compounds \(X\) andY have retention times of \(18.40\) and \(20.63\) min, respectively, on a 30 \(\mathrm{cm}\) column. If the peak widths at the peak bases are \(1.11\) and \(1.21\) min, respectively, calculate: (a) The resolution factor for the two peaks. (b) The efficiency of each peak.

Short Answer

Expert verified
The resolution factor for the peaks of the two compounds is 1.96. The efficiency of peak 1 is 48876.51 and that of peak 2 is 45684.70

Step by step solution

01

Calculate resolution

We calculate the resolution using the formula: \(Resolution = \frac{R2(peak 2) - R1(peak 1)}{0.5*(W2+W1)}\), where \(R1\) and \(R2\) are the retention times of the two peaks and \(W1\) and \(W2\) are the widths of the two peaks at their bases. Substituting the given values: \(Resolution = \frac{20.63 - 18.40}{0.5*(1.11 + 1.21)}\)
02

Solve for resolution

We solve for resolution to get the resolution factor for the two peaks. This is done by carrying out the operations in the formula. \(Resolution = 1.96\)
03

Calculate efficiency

We calculate the efficiency using the formula: \(N = 16*(t_R/W)^2\), where \(N\) is the efficiency, \(t_R\) is the retention time, and \(W\) is the width of the peak at its base. We do this for each peak. For peak 1: \(N1 = 16*(18.40/1.11)^2\) and for peak 2: \(N2 = 16*(20.63/1.21)^2\)
04

Solve for efficiency

We solve the formula to get the efficiency of each peak. For Peak 1: \(N1 = 48876.51\) and for Peak 2: \(N2 = 45684.70\)

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