The Beer-Lambert relationship, eqn [29.3] is written in the form \(A=\varepsilon / C]\). Rearrange, in the form: (a) \([C]=\) (b) \(\varepsilon=\)

Short Answer

Expert verified
The rearranged form of the Beer-Lambert relationship is: \n(a) \([C]=\frac{A}{\varepsilon}\) \n(b) \(\varepsilon=\frac{A}{C}\)

Step by step solution

01

Solve for concentration C

To solve for the concentration, C, we start from the given equation \(A=\varepsilon C\). We need to get C on one side of the equation. We can do this by dividing both sides of the equation by the molar absorptivity, \(\varepsilon\). Doing this gives us the equation for C as \([C]=\frac{A}{\varepsilon}\)
02

Solve for molar absorptivity \(\varepsilon\)

Next, we move to getting the equation for the molar absorptivity, \(\varepsilon\). Starting from the original Beer-Lambert relationship equation \(A=\varepsilon C\), we again need to isolate \(\varepsilon\) on one side of the equation. We can do this by dividing both sides of the equation by the concentration, C. This gives us the equation for \(\varepsilon\) as \(\varepsilon=\frac{A}{C}\)

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