Carry out calculations involving percentages. Answer the following questions, giving your answers to two decimal places: (a) What is \(6 / 35\) ths expressed as a percentage? (b) What is \(0.0755\) expressed as a percentage? (c) What is \(4.35 \%\) of \(322 ?\) (d) A rat's weight increased from \(55.23\) to \(75.02 \mathrm{~g}\). What is the \% increase in its weight?

Short Answer

Expert verified
The answers are (a) 17.14%, (b) 7.55%, (c) 13.997, (d) 35.83%

Step by step solution

01

Convert Fraction to Percentage

To convert a fraction to a percentage, divide the numerator by the denominator and then multiply the result by 100. So to find the percentage of \(6 / 35\), perform the following calculation: \((6 ÷ 35) * 100\).
02

Convert Decimal to Percentage

To convert a decimal to a percentage, multiply the decimal by 100. Thus, \(0.0755 * 100\) equals the decimal expressed as a percentage.
03

Find Percentage of a Number

To find a certain percentage of a number, multiply that percentage (in decimal form) by the number. So to find \(4.35\%\) of \(322\), the calculation would be \((4.35 ÷ 100) * 322 \).
04

Calculate Percentage Increase

The percentage increase can be calculated as follows: \(((Final Value - Initial Value) ÷ Initial Value) *100\). Hence, to find the percent increase from \(55.23 g\) to \(75.02 g\), the calculation would be \(((75.02 - 55.23) ÷ 55.23) * 100\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free