Chapter 2: Problem 122
The e quantum numbers of four electrons (e1 to e4) are given below : $$ \begin{array}{ccccccccc}n & l & m & s & & n & l & m & s \\ 3 & 0 & 0 & +1 / 2 & e 2 & 4 & 0 & 0 & 1 / 2 \\ 3 & 2 & 2 & -1 / 2 & e 4 & 3 & 1 & -1 & 1 / 2\end{array} $$ \(\begin{array}{r}\text { The quar } \\ e 1 & n \\ e 3 & 3\end{array}\) The correct order of decreasing energy of these electrons is: (a) \(e 4>e 3>e 2>e 1\) (b) \(e 2>e 3>e 4>e 1\) (c) \(e 3>e 2>e 4>e 1\) (d) \(e 1>e 4>e 2>e 3\)
Short Answer
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Key Concepts
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