Chapter 4: Problem 18
A sample of an ideal gas is expanded \(1 \mathrm{~m}^{3}\) to \(3 \mathrm{~m}^{3}\) in a reversible process for which \(P=K V^{2}\), with \(K=6 \mathrm{bar} / \mathrm{m}^{6}\). Work done by the gas is : (a) \(5200 \mathrm{~kJ}\) (b) \(15600 \mathrm{~kJ}\) (c) \(52 \mathrm{~kJ}\) (d) \(5267.6 \mathrm{~kJ}\)
Short Answer
Step by step solution
Title - Understand the Given Data
Title - Apply the Work Formula for Expansion
Title - Integrate with Limits
Title - Calculate the Integral
Title - Convert Units to kJ
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ideal Gas Law
The ideal gas law is crucial in understanding how gases respond to changes in temperature, pressure, and volume, and serves as the basis for deriving other important thermodynamic equations and processes, such as the one involved in our textbook problem.
Reversible Expansion
In a reversible expansion, the external pressure applied to the gas matches the internal pressure of the gas at every moment, allowing for the most efficient work extraction. This concept is theoretical but provides a useful model for understanding the limits of efficiency in physical processes and helps to establish a foundation for calculating work in thermodynamic systems.
Integration in Thermodynamics
For example, when dealing with the work done by a gas under variable pressure, we use integration to sum up the work done at every infinitesimal increase in volume. Integration can be visualized graphically as the area under the curve on a pressure-volume (P-V) diagram. The correct setup of the integral, with accurate limits and integrated function, is crucial for determining the work or heat associated with a given thermodynamic process.
Pressure-Volume Work
The general formula for P-V work in a reversible process is expressed as \(W = \[ \int_{V_1}^{V_2} P\text{d}V\] \) where W is the work done by or on the system, P is the pressure, and V is the volume. The limits of integration, \(V_1\) and \(V_2\), are the initial and final volumes of the gas, respectively. If the process is described by a specific P-V relationship, as was the case in our exercise where \(P = KV^2\), we can substitute this into the integral to calculate the total work done.