Chapter 4: Problem 28
Which of the following exprésstons' is 'true for an ideal gas ? (a) \(\left(\frac{\partial V}{\partial T}\right)_{P}=0\) (b) \(\left(\frac{\partial P}{\partial T}\right)_{V: n}=0^{6}\) (c) \(\left(\frac{\partial U}{\partial V}\right)_{T}=0\) (d) \(\left(\frac{\partial U}{\partial T}\right)_{V}=0\)
Short Answer
Expert verified
Option (c) \(\left(\frac{\partial U}{\partial V}\right)_{T}=0\) is true for an ideal gas because the internal energy of an ideal gas is independent of its volume.
Step by step solution
01
Understanding Ideal Gas Behavior
To solve this exercise, it's important to first understand the behavior of an ideal gas. An ideal gas follows the ideal gas law, which states that PV = nRT, where P is pressure, V is volume, T is temperature, n is the number of moles, and R is the ideal gas constant. As per this law, for an ideal gas, the volume (V) is directly proportional to temperature (T) when pressure (P) is constant, and the pressure (P) is directly proportional to temperature (T) when volume (V) is constant.
02
Analyzing Option (a)
Option (a) states that \(\left(\frac{\partial V}{\partial T}\right)_{P}=0\). This would mean that volume is not changing with temperature at constant pressure, which is not true for an ideal gas since, according to the ideal gas law, volume should change if temperature changes at constant pressure.
03
Analyzing Option (b)
Option (b) states that \(\left(\frac{\partial P}{\partial T}\right)_{V; n}=0^{6}\) which implies that the pressure does not change with temperature at constant volume and a fixed amount of gas. This is incorrect according to the ideal gas law because it shows pressure is directly proportional to temperature at constant volume.
04
Analyzing Option (c)
Option (c) \(\left(\frac{\partial U}{\partial V}\right)_{T}=0\) refers to the change in internal energy (U) with volume at a constant temperature. For an ideal gas, the internal energy is a function of temperature only and does not depend on the volume. Hence, this expression is true for an ideal gas as the internal energy will not change with volume at constant temperature.
05
Analyzing Option (d)
Option (d) \(\left(\frac{\partial U}{\partial T}\right)_{V}=0\) suggests that the internal energy does not change with temperature at constant volume, which is not correct for an ideal gas. The internal energy of an ideal gas depends only on temperature and will change if the temperature changes.
06
Identifying the Correct Statement
Based on the analysis of the given options and understanding the properties of an ideal gas, we can determine that option (c) is the correct expression that is true for an ideal gas.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ideal Gas Behavior
Understanding the behavior of an ideal gas is fundamental in thermodynamics, particularly when working with gas-related problems. An ideal gas is a hypothetical gas whose molecules occupy negligible space and have no interactions, and it exactly follows the ideal gas law, given by the equation
This simple yet powerful equation encapsulates how changes in one state variable, such as temperature, will affect others, if certain conditions remain constant. For example, if we hold pressure constant (isobaric process), the volume will increase as the temperature increases. Conversely, if volume is kept constant (isochoric process), an increase in temperature will lead to an increase in pressure. These relationships are rooted in the kinetic theory of gases, which states that temperature reflects the average kinetic energy of gas molecules. More movement (higher temperature) generally means more pressure or more volume.
It's crucial to note that ideal gas behavior is an approximation. Real gases exhibit ideal behavior only under low pressure and high temperature conditions. At high pressures and low temperatures, the interactions between gas molecules become significant, and the volume occupied by the molecules themselves can no longer be neglected.
PV = nRT
, where P
stands for pressure, V
for volume, T
for temperature, n
for the number of moles, and R
for the ideal gas constant. This simple yet powerful equation encapsulates how changes in one state variable, such as temperature, will affect others, if certain conditions remain constant. For example, if we hold pressure constant (isobaric process), the volume will increase as the temperature increases. Conversely, if volume is kept constant (isochoric process), an increase in temperature will lead to an increase in pressure. These relationships are rooted in the kinetic theory of gases, which states that temperature reflects the average kinetic energy of gas molecules. More movement (higher temperature) generally means more pressure or more volume.
It's crucial to note that ideal gas behavior is an approximation. Real gases exhibit ideal behavior only under low pressure and high temperature conditions. At high pressures and low temperatures, the interactions between gas molecules become significant, and the volume occupied by the molecules themselves can no longer be neglected.
Partial Derivatives in Thermodynamics
In thermodynamics, partial derivatives provide a powerful tool for understanding how a system's properties change with respect to one another while holding other variables constant. They are essential when we analyze the relationships between different state variables of a system, such as pressure, volume, temperature, and internal energy.
For instance, the partial derivative
The use of subscripts, such as V or P, signifies that these variables remain constant during the differentiation process. Mastery of partial derivatives is essential for students to fully comprehend not just the mathematical formulations, but also the physical implications of various thermodynamic processes.
For instance, the partial derivative
\( \left(\frac{\partial V}{\partial T}\right)_P \)
represents how volume V changes with temperature T when pressure P is kept constant. Intuitively, if this derivative is positive, it means that as the temperature increases, the volume increases, which is consistent with Charles's Law. On the other hand, a partial derivative like \( \left(\frac{\partial P}{\partial T}\right)_{V, n} \)
indicates how pressure P varies with temperature T when both volume V and the number of moles n are fixed, directly illustrating Gay-Lussac's Law. The use of subscripts, such as V or P, signifies that these variables remain constant during the differentiation process. Mastery of partial derivatives is essential for students to fully comprehend not just the mathematical formulations, but also the physical implications of various thermodynamic processes.
Internal Energy of Gases
The concept of internal energy in thermodynamics is pivotal in understanding how energy is stored within a gas. The internal energy, denoted as
In mathematical terms, for an ideal gas, the internal energy depends only on temperature and can be represented by
Furthermore, recognizing that an ideal gas does not have potential energy due to particle interactions, we can see why the internal energy of an ideal gas would not be affected by changes in volume at a constant temperature. This understanding is essential for solving problems related to the work done by or on the gas, as well as predicting how energy will be transferred in the form of heat or work during a process.
U
, encompasses all the energy contained within a system, which for gases, predominantly comprises the kinetic energy of the moving gas particles. According to the kinetic theory, this energy increases as the temperature rises, implying that the internal energy of an ideal gas is directly related to its temperature. In mathematical terms, for an ideal gas, the internal energy depends only on temperature and can be represented by
\( U = \frac{3}{2}nRT \)
for a monatomic ideal gas. This means that when we look at a partial derivative such as \( \left(\frac{\partial U}{\partial V}\right)_T \)
, we expect it to be zero because changing the volume while keeping temperature constant should not affect the internal energy of an ideal gas. This property simplifies many thermodynamic calculations and is a cornerstone in the understanding of ideal gas processes. Furthermore, recognizing that an ideal gas does not have potential energy due to particle interactions, we can see why the internal energy of an ideal gas would not be affected by changes in volume at a constant temperature. This understanding is essential for solving problems related to the work done by or on the gas, as well as predicting how energy will be transferred in the form of heat or work during a process.