Chapter 4: Problem 48
Calculate average molar heat capacity at constant volume of gaseous mixture contained 2 mole of each of two ideal gases \(A\left(C_{\mathrm{v}, m}=\frac{3}{2} R\right)\) and \(B\left(C_{\mathrm{v}, m}=\frac{5}{2} R\right):\) (a) \(R\) (b) \(2 R\) (c) \(3 R\) (d) \(8 R\)
Short Answer
Expert verified
The average molar heat capacity at constant volume for the gaseous mixture is \(2R\).
Step by step solution
01
Understand the concept of molar heat capacity at constant volume for an ideal gas
The molar heat capacity at constant volume (\( C_{\text{v}, m} \)) of an ideal gas is the amount of heat required to raise the temperature of one mole of a substance by one degree Celsius at constant volume. In this exercise, we are given the molar heat capacities of two ideal gases A and B.
02
Calculate the total heat capacity at constant volume
Since both gases are ideal and in equal amounts (2 moles each), the total heat capacity of the mixture at constant volume (\( C_{\text{v}, total} \)) is the sum of the individual heat capacities of gas A and gas B. This can be calculated using the formula: \[ C_{\text{v}, total} = n_A \times C_{\text{v}, m}(A) + n_B \times C_{\text{v}, m}(B) \] where \( n_A \) and \( n_B \) are the number of moles of gases A and B respectively.
03
Substitute the given values
Substitute the given values into the equation: \[ C_{\text{v}, total} = 2 \text{ moles} \times \left(\frac{3}{2} R\right) + 2 \text{ moles} \times \left(\frac{5}{2} R\right) \] Simplify to find the total heat capacity of the mixture.
04
Calculate the average molar heat capacity at constant volume
To find the average molar heat capacity at constant volume (\( \bar{C}_{\text{v}, m} \)) for the mixture, divide the total heat capacity by the total number of moles in the mixture: \[ \bar{C}_{\text{v}, m} = \frac{C_{\text{v}, total}}{n_{total}} \] where \( n_{total} \) is the total number of moles of the gas mixture.
05
Solve for the average molar heat capacity
After substituting the values and simplifying, calculate \( \bar{C}_{\text{v}, m} \) to get the final result. The calculation should yield: \[ \bar{C}_{\text{v}, m} = \frac{2 \times \frac{3}{2}R + 2 \times \frac{5}{2}R}{2 + 2} \] Simplify this to find the answer among the given options.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ideal Gas Law
The ideal gas law is a fundamental equation in physical chemistry that describes the behavior of ideal gases. It combines several gas laws into one, expressing the relationship between pressure (P), volume (V), temperature (T), and the number of moles (n) of an ideal gas.
Ideal gases are hypothetical gases that perfectly follow the gas laws under all conditions of temperature and pressure. The law is typically stated as:
\[ PV = nRT \]
Here, R is the universal gas constant, which appears in the molar heat capacity equations from the textbook exercise. The ideal gas law assumes no interactions between gas molecules and that the volume occupied by the molecules themselves is negligible compared to the volume of their container.
Understanding this law is crucial in solving problems related to gas mixtures and their heat capacities, as seen in the example exercise where the law aids in conceptualizing the behavior of the gas mixture when heat is applied at a constant volume.
Ideal gases are hypothetical gases that perfectly follow the gas laws under all conditions of temperature and pressure. The law is typically stated as:
\[ PV = nRT \]
Here, R is the universal gas constant, which appears in the molar heat capacity equations from the textbook exercise. The ideal gas law assumes no interactions between gas molecules and that the volume occupied by the molecules themselves is negligible compared to the volume of their container.
Understanding this law is crucial in solving problems related to gas mixtures and their heat capacities, as seen in the example exercise where the law aids in conceptualizing the behavior of the gas mixture when heat is applied at a constant volume.
Thermodynamics
Thermodynamics is the branch of physical science that deals with the relations between heat and other forms of energy such as mechanical, electrical, or chemical energy. It encompasses the principles governing the conversion of energy and its transfer from one body to another. In the context of our textbook problem, we are particularly concerned with the first law of thermodynamics, which is also known as the conservation of energy.
This principle asserts that energy cannot be created or destroyed, only transformed from one form to another. The heat capacity of a substance is a measure of how much energy in the form of heat is needed to increase its temperature, which is central to thermodynamics.
The molar heat capacity specifically indicates the amount of heat required to raise the temperature of one mole of a substance by one degree Celsius (or one Kelvin). For an ideal gas, this can be measured at constant volume (\( C_{v, m} \)) or at constant pressure (\( C_{p, m} \)).
This principle asserts that energy cannot be created or destroyed, only transformed from one form to another. The heat capacity of a substance is a measure of how much energy in the form of heat is needed to increase its temperature, which is central to thermodynamics.
The molar heat capacity specifically indicates the amount of heat required to raise the temperature of one mole of a substance by one degree Celsius (or one Kelvin). For an ideal gas, this can be measured at constant volume (\( C_{v, m} \)) or at constant pressure (\( C_{p, m} \)).
Physical Chemistry
Physical chemistry is a sub-discipline of chemistry that focuses on understanding the physical properties of molecules, the forces that act upon them, and the physical basis of chemical reactions. It merges principles of physics and chemistry to explain how chemical systems behave.
In the context of the textbook exercise, physical chemistry principles help us understand the molar heat capacity of gases. The exercise illustrates a physical chemistry concept by calculating the heat capacity of a gas mixture, incorporating the molar heat capacities of the individual gases and using the arithmetic mean to find the average.
Such calculations are vital in physical chemistry for predicting the outcomes of reactions, understanding the energetics of molecular interactions, and designing experiments. It requires a firm grasp of concepts like the ideal gas law and the principles of thermodynamics to effectively engage with and solve problems in this field of study.
In the context of the textbook exercise, physical chemistry principles help us understand the molar heat capacity of gases. The exercise illustrates a physical chemistry concept by calculating the heat capacity of a gas mixture, incorporating the molar heat capacities of the individual gases and using the arithmetic mean to find the average.
Such calculations are vital in physical chemistry for predicting the outcomes of reactions, understanding the energetics of molecular interactions, and designing experiments. It requires a firm grasp of concepts like the ideal gas law and the principles of thermodynamics to effectively engage with and solve problems in this field of study.