Including activity coefficient, find the concentration of Ba2+in 0.100M(CH3)4NIO3solution saturated with Ba(IO3)2.

Short Answer

Expert verified

The concentration of Ba2+in a 0.001MCH34NIO3solution saturated with BaIO32is6.6×10-7M

Step by step solution

01

Step 1:Finding the activity coefficient of aqueous solution Ba2+ and IO3-.

In the given problem, we need to find the activity coefficient along with concentration of Ba2+in a 0.001MCH34NIO3solution saturated with BaIO32.

The solubility of BaIO32is not quite expressed. So we will assume that BaIO32contributes negligible IO3-to0.100MCH34NIO3.

cIO3-=0.1M

From the Table 8-1, we can know that the values are,

γBa2+=0.380γIO3-=0.775

02

Finding the concentration of  Ba2+in a 0.001M(CH3)4NIO3 solution saturated with  Ba(IO3)2 using equilibrium constant equation.

Now, we will use equilibrium constant equation,

Ksp=1.5×10-9Ksp=cBa2+γ(Ba2+)×c2IO3-1.5×10-9=cBa2+×0.380×0.12×0.7752cBa2+=6.6×10-7M

Thus the concentration of Ba2+in a 0.001MCH34NIO3solution saturated with BaIO32is 6.6×10-7M

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