Chapter 8: Q31P (page 186)

Ion pairing. As in Problem $8 - 30$ , find the concentration, ionic strength, and ion pair fraction in localid="1654942556135" $0.025 F {Na}_{2} {SO}_{4}$ . Assume that the size of the ${NaSO}^{-}_{4} = 500 pm$

Short Answer

Expert verified

Thus the Ionic Strength and Ion Pair Fraction of $0.025 F {Na}_{2} {SO}_{4}$ is 0.07051M and 9%

Step by step solution

Step 1:Calculating the Ionic Strength and Ion Pair Fraction.

This is also a task that need to be performed in the Excel. And the values will be,

$[{Na}^{+}] = 0.04775 M [{SO}^{2 -}_{4}] = 0.02275 M [{NaSO}^{-}_{4}] = 0.002246 M$

Ionic Strength =0.070514M

Ion Pair Fraction =9%

Step 2:Ionic Strength and Ion Pair Fraction of 0.025 F Na2SO4

Thus the Ionic Strength and Ion Pair Fraction of $0.025 F {Na}_{2} {SO}_{4}$ is $0.07051 M$ and 9%

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Ion pairing. As in Problem $8 - 30$ , find the concentration, ionic strength, and ion pair fraction in localid="1654942556135" $0.025 F {Na}_{2} {SO}_{4}$ . Assume that the size of the ${NaSO}^{-}_{4} = 500 pm$

Short Answer

Step by step solution

Step 1:Calculating the Ionic Strength and Ion Pair Fraction.

Step 2:Ionic Strength and Ion Pair Fraction of 0.025 F Na2SO4

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Ion pairing. As in Problem 8-30, find the concentration, ionic strength, and ion pair fraction in localid="1654942556135" 0.025FNa2SO4. Assume that the size of theNaSO-4=500pm

Short Answer

Step by step solution

Step 1:Calculating the Ionic Strength and Ion Pair Fraction.

Step 2:Ionic Strength and Ion Pair Fraction of 0.025 F Na2SO4

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Ionic and Molecular Compounds

Chemical Reactions

Chemistry Branches

Organic Chemistry

Making Measurements

Kinetics

Study anywhere. Anytime. Across all devices.

Ion pairing. As in Problem $8 - 30$ , find the concentration, ionic strength, and ion pair fraction in localid="1654942556135" $0.025 F {Na}_{2} {SO}_{4}$ . Assume that the size of the ${NaSO}^{-}_{4} = 500 pm$