Find [Hg22+] in equilibrium with 0.010MKCl saturated withHg2Cl2.

Short Answer

Expert verified

The value of [Hg22+] in equilibrium with 0.010M KCI saturated Hg2Cl2is2.2×10-14M

Step by step solution

01

Concept used.

Solubility product (Ksp):

The product of a substance's dissolved ion concentrations raised to the power of their stoichiometric coefficients is used to calculate the solubility product.

02

Step 2: Calculate the value of [Hg22+].

Assume that Hg2Cl2each contribute a negligible amount of Cl-to 0.010MKCl. This is due to the low solubility of Hg2Cl2.

From the table 8-1 and given information the required values are,

μ=0.010MCl-=0.010MγHg2+=0.660andγCr=0.899

Calculate the value ofHg22+ using the equation for the solubility product

Ksp=1.2×10-18=Hg22+γlg2+Cl-2γ2Cr2=Hg22+0.6600.0120.8992Hg22+=2.2×10-14M

The value of Hg22+in equilibrium with 0.010M KCI saturated Hg2Cl2is role="math" localid="1663411773731" 2.2×10-14M

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