Chapter 6: Q CE (page 140)

Find $[{La}^{3 +}]$ in the solution when excess solid lanthanum iodate, $La {({IO}_{3})}_{3}$ , is stirred with until the system reaches equilibrium. Assume that ${IO}_{3}^{-}$ from ${La}_{3} {({IO}_{3})}_{3}$ is negligible compared with ${IO}_{3}^{-}$ from ${LiOO}_{3}$ .

Short Answer

Expert verified

$[{La}^{3 -}]$ in the solution was found to be $8.0 x 10 {}^{8}M$

Step by step solution

solubility product

When solid lanthanum iodide $La {({IO}_{3})}_{3}$ is stirred with $0.050 M$ lithium iodate $({LiO}_{3})$ up to it attains an equilibrium, the $[{La}^{3 -}]$ in the solution has to be calculated.

Solubility product role="math" localid="1663410124986" $(K_{s p})$ :

It is defined as the mathematical product of the dissolved ion's concentration raised to the power of its stoichiometric coefficient.

$M_{y} X_{z (s)} {yM}^{z +}_{(aq)} + {zX}^{y -}_{(aq)} K_{sp} = {[M^{z}]}^{y} {[X^{y -}]}^{z}$

the concentration of Iodide should not be changed

$K_{sp}$ for $La {({IO}_{3})}_{3}$ is very small. That is $(1.0 x 10^{- 11})$ . Therefore, imagine that the concentration of Iodide should not be changed by the minimum amount of $La {({IO}_{3})}_{3}$ that dissolve.

$[{La}^{2}] = \frac{K_{sp}}{{[{IO}_{3}^{-}]}^{3}} = \frac{1.0 x 10^{- 11}}{{(0.050)}^{3}} [{La}^{3 -}] = 8.30 x 10^{- 8} M$

The answer proved that the assumption that locate formed from $La {({IO}_{3})}_{3} 0.050 M$ .

$[{La}^{3 -}]$ in the solution was found to be $8.0 x 10^{8} M$

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Find $[{La}^{3 +}]$ in the solution when excess solid lanthanum iodate, $La {({IO}_{3})}_{3}$ , is stirred with until the system reaches equilibrium. Assume that ${IO}_{3}^{-}$ from ${La}_{3} {({IO}_{3})}_{3}$ is negligible compared with ${IO}_{3}^{-}$ from ${LiOO}_{3}$ .

Short Answer

Step by step solution

solubility product

the concentration of Iodide should not be changed

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Find [La3+]in the solution when excess solid lanthanum iodate, La(IO3)3, is stirred with until the system reaches equilibrium. Assume that IO3-from La3(IO3)3is negligible compared with IO3-from LiOO3.

Short Answer

Step by step solution

solubility product

the concentration of Iodide should not be changed

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Ionic and Molecular Compounds

Nuclear Chemistry

Chemistry Branches

The Earths Atmosphere

Kinetics

Chemical Analysis

Study anywhere. Anytime. Across all devices.

Find $[{La}^{3 +}]$ in the solution when excess solid lanthanum iodate, $La {({IO}_{3})}_{3}$ , is stirred with until the system reaches equilibrium. Assume that ${IO}_{3}^{-}$ from ${La}_{3} {({IO}_{3})}_{3}$ is negligible compared with ${IO}_{3}^{-}$ from ${LiOO}_{3}$ .