Find[Cu2+]in a solution saturated with Cu4(OH)6(so4) if [OH-] is fixed at 1.0×10-6M . Note that Cu4(OH)6(so4)gives 1mol of SO42-4 mol for of Cu2+.

Cu4(OH)6(so4)(s)4Cu2++6OH-+SO42-Ksp=2.3×10-69

Short Answer

Expert verified

[Cu2+] was calculated as3.9×10-7M

Step by step solution

01

Definition of solubility product

Solubility product Ksp:

It is defined as the mathematical product of the concentration of the dissolved constituent ions raised up to the power of their stoichiometric coefficient.

MyXzsyMz+(aq)+zXy-aqKsp=Mz+yXy-z

02

Calculate the concentration of [Cu2+]The dissociation reaction is:

Cu4(OH)6(so4)(s)4Cu2++6OH-+SO42-

From the balanced reversible reaction, it is seen that 1 mol Cu4(OH)6(so4)of dissociates to give 4 mol Cu2+of and 1 mol of SO42-.

Lets take 4x=Cu2+; then X=SO42-

K=Cu2+4OH-6SO42-2.3×10-69=4x4×1.0×10-6×x2.3×10-69=x5×1.0×10-6×256

x=Cu2+=2.3×10-69256×1.0×10-6615=3.9×10-7M

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