For the reaction Li++H2OLi(OH)(aq)+H+,KLi=2.3×10-14. Combine this reaction with the reaction to find the equilibrium constant for the reaction Li++OH-Li(OH)(aq).

Short Answer

Expert verified

The equilibrium constant (K) for the reaction of Li++OH-Li(OH)aq was calculated as 2.3.

Step by step solution

01

Define the formula for Kb.

The value of can be calculated as:

Kb=BH+OHB

Where Kbis called a base dissociation constant.

The value of Kwis calculated by the formula:

KW=Ka×Kb

02

Find the equilibrium constant.

Given:

KLi=2.3×10-14MKw=[H+][OH-]Kw=1.0×10-14

Now the equilibrium constant for the given reaction:

H+OH-H2OK=1/Kw=1/1.0×10-14Li++H2OLiOHaq+H+KLi=2.3×10-14Li++OH-LiOHaqK=1/Kw.KLi

K=11.0×10-14×2.3×10-14=2.3

Thus, the equilibrium constant (K) for the reaction of Li++OH-Li(OH)aqwas calculated to be 2.3.

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