Chapter 6: Q1TY (page 121)

For the reaction ${Li}^{+} + H_{2} O ⇌ Li (OH) (aq) + H^{+}, K_{L} i = 2.3 \times 10^{- 14}$ . Combine this reaction with the reaction to find the equilibrium constant for the reaction ${Li}^{+} + {OH}^{-} ⇌ Li (OH) (aq) .$

Short Answer

Expert verified

The equilibrium constant (K) for the reaction of ${Li}^{+} + {OH}^{-} ⇌ Li (OH)_{(aq)}$ was calculated as 2.3.

Step by step solution

Define the formula for Kb.

The value of can be calculated as:

$K_{b} = \frac{[{BH}^{+}] [OH]}{[B]}$

Where $K_{b}$ is called a base dissociation constant.

The value of $K_{w}$ is calculated by the formula:

$K_{W} = K_{a} \times K_{b}$

Find the equilibrium constant.

Given:

$K_{Li} = 2.3 \times 10^{- 14} M K_{w} = [H^{+}] [{OH}^{-}] K_{w} = 1.0 \times 10^{- 14}$

Now the equilibrium constant for the given reaction:

$\frac{H^{+} {OH}^{-} H_{2} O K = 1 / K_{w} = 1 / 1.0 \times 10^{- 14} {Li}^{+} + H_{2} O Li {(OH)}_{(aq)} + H^{+} K_{Li} = 2.3 \times 10^{- 14}}{{Li}^{+} + {OH}^{-} Li {(OH)}_{aq} K = 1 / K_{w .} K_{Li}}$

$K = \frac{1}{1.0 \times 10^{- 14}} \times 2.3 \times 10^{- 14} = 2.3$

Thus, the equilibrium constant (K) for the reaction of ${Li}^{+} + {OH}^{-} ⇌ Li (OH)_{(aq)}$ was calculated to be 2.3.

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For the reaction ${Li}^{+} + H_{2} O ⇌ Li (OH) (aq) + H^{+}, K_{L} i = 2.3 \times 10^{- 14}$ . Combine this reaction with the reaction to find the equilibrium constant for the reaction ${Li}^{+} + {OH}^{-} ⇌ Li (OH) (aq) .$

Short Answer

Step by step solution

Define the formula for Kb.

Find the equilibrium constant.

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For the reaction Li++H2O⇌Li(OH)(aq)+H+,KLi=2.3×10-14. Combine this reaction with the reaction to find the equilibrium constant for the reaction Li++OH-⇌Li(OH)(aq).

Short Answer

Step by step solution

Define the formula for Kb.

Find the equilibrium constant.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Organic Chemistry

Nuclear Chemistry

Chemical Reactions

The Earths Atmosphere

Ionic and Molecular Compounds

Study anywhere. Anytime. Across all devices.

For the reaction ${Li}^{+} + H_{2} O ⇌ Li (OH) (aq) + H^{+}, K_{L} i = 2.3 \times 10^{- 14}$ . Combine this reaction with the reaction to find the equilibrium constant for the reaction ${Li}^{+} + {OH}^{-} ⇌ Li (OH) (aq) .$