Find [Pb2+],PbI2(aq),and [PbI3-]in a saturated solution of PbI2(s)with [I-]=0.10M.

Short Answer

Expert verified

Theconcentrationof[Pb2+]is7.9×10-7MTheconcentrationof[PbI2aq]is1.1×10-5MTheconcentrationof[PbI3]is6.6×10-6M

Step by step solution

01

Define the solubility product

It is defined as the product of the dissolved ion concentration raised to the power of the stoichiometric coefficient.

MyXzsKspMz+(aq)+zXy-(aq)Ksp=[Mz+]y[Xy-]z

The solubility product is very helpful in predicting whether a salt precipitates in a solution.

02

Find the concentration.

For the reaction:

PbI2(s)Pb+2+2I-Ksp=7.9×10-9

Ksp=[Pb+2][I-]2

Pb2+=Ksp/I-2=7.9×10-9/0.102=7.9×10-7M

03

Find the concentration.

Pb2++2I-β2PbI2β2=1.4×103[PbI2aq]=β2[Pb2+][I-]2

=1.1×10-5M

04

Find the concentration.

Pb2++3I-β3PbI3-β3=8.3×103

Concentration of Pbl3-

Pbl3-=β3Pb2+l-3=6.6×10-6M

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Most popular questions from this chapter

Reaction 6-8 is allowed to come to equilibrium in a solution initially containing0.0100MBrO3-,0.0100MCr3+ and 1.00MH+. To find the concentrations at equilibrium, we construct the table at the bottom of the page showing initial and final concentrations. We use the stoichiometry coefficients of the reaction to say that if xmolof Br- are created, then we must also make x mol of Cr2O72- and 8x mol of H+. To produce x mol of Br-, we must have consumed x mol of Br-O3- and 2x mol of Cr3+.

(a) Write the equilibrium constant expression that you would use to solve for x to find the concentrations at equilibrium. Do not try to solve the equation.

(b) Because K=1×1011, we suppose that the reaction will go nearly "to completion." That is, we expect both the concentration of Br-and Cr2O72-to be close to 0.00500M an equilibrium. (Why?) That is, x0.00500M. With this value of x,[H+]=1.00+8x=1.04Mand [BrO3-]=0.0100-x=0.0050M. However, we cannot say [Cr3+]=0.0100-2x=0, because there must be some small concentration of Cr3+at equilibrium. Write [Cr3+]for the concentration of Cr3+and solve for [Cr3+]. The limiting reagent in this example is Cr3+. The reaction uses up before consuming BrO3-.

BaCl2?H2O(s)loses water when it is heated in an oven:

BaCl2H2O(s)BaCl2(s)+H2O(g)

ΔH°=63.11kJ/molat25°C

ΔS°=+148J/(Kmol)at25°C

a) Write the equilibrium constant for this reaction. Calculate the vapour pressure of gaseous H2O(PH2O) above BaCl2H2Oat 298K.

(b) If H°and S°are not temperature dependent (a poor assumption), estimate the temperature at which PH2O above BaCl2H2O(s)will be 1 bar.

Find [La3+]in the solution when excess solid lanthanum iodate, La(IO3)3, is stirred with until the system reaches equilibrium. Assume that IO3-from La3(IO3)3is negligible compared with IO3-from LiOO3.

Identify the Bronsted-Lowry acids among the reactants in the following reactions:

(a) KCN+HIHCN+KI

(b)PO43-+H2OHPO42-+OH-

AlthoughKOH,RbOHand CsOHhave little association between metal and hydroxide in aqueous solution,Li+andNa+do form complexes with:

role="math" localid="1663390733265" Li++OH-LiOH(aq)K1=[LiOH(aq)][Li+][OH-]=0.83

Na++OH-NaOH(aq)K1=0.20

Prepare a table like the one in Exercise 6-B showing initial and final Concentrations of Na++OH-NaOH(aq)and (aq)insolution. Calculate the fraction of sodium in the form (aq)at equilibrium.

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