Use Table 6-1 to find the [H+]in water at 100°Cand at0°C.

Short Answer

Expert verified

H+in the water at 100°C and at 0°Care found to be 7.4×10-7 and ,3.4×10-8 respectively.

Step by step solution

01

Define the formula for finding Kb.

The value of can be calculated as:

Kb=[BH+][OH][B]

Where Kbis called the base dissociation constant.

02

Step 2: Calculate the Kw.

Given:

At100°C,Kw=5.43×10-13

At0°CKw=1.15×10-15

Kw=[H+][OH-]

H+in the water at100°C

Kw=5.43×10-14=[H+][OH-]=[x][x]=[x]2x=5.43×10-14=7.4×10-7

At 0°C

Kw=1.15×10-15=[H+][OH-]=[x][x]=[x]2x=1.15×10-15=3.4×10-8

Using temperature dependent of Kwavalues H+in the water.

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