Chapter 6: Q8P (page 141)

For the reaction ${HCO}_{3}^{-} ⇌ H^{+} + " {CO}_{3}^{2 -}$ , $ΔG ° = + 59.0 kJ / mol$ at $298.15 K$ . Find the value of Kfor the reaction.

Short Answer

Expert verified

The value of K for the given reaction is $5 \times 10^{- 11}$ .

Step by step solution

Equilibrium constant

Equilibrium constant (K): In the equilibrium reaction, the ratio is between the concentration of the reactant and the concentration of the product. If K's value is smaller than 1, the reaction should be moved to the left; if K is more than 1, the reaction should be moved to the right.

$ΔG ° = - RT \ln K$

$K = e^{(- ∆ G ° / RT)}$

Here,

$∆ G °$ is the change in free energy.

K is the equilibrium constant.

R is Gas constant 8.314

T is Temperature.

The value of K for the given reaction.

The given reaction is:

${HCO}_{3}^{-} ⇌ H^{+} + {CO}_{3}^{2 -} ΔG ° = + 59.0 kJ / mol$

Temperature $= 298.15 K$

$K = e^{(- ∆ G ° / R T)} = e^{- (59.0 \times 10^{3} J / m o l) / (8.314472 J / K . m o l) (298.15 K)} = e^{- (59.0 \times 10^{3} J / m o l) / 2478.9598 J / m o l} = e^{- (23.80)} = 5 \times 10^{- 11}$

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For the reaction ${HCO}_{3}^{-} ⇌ H^{+} + " {CO}_{3}^{2 -}$ , $ΔG ° = + 59.0 kJ / mol$ at $298.15 K$ . Find the value of Kfor the reaction.

Short Answer

Step by step solution

Equilibrium constant

The value of K for the given reaction.

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For the reactionHCO3-⇌H++"CO32-, ΔG°=+59.0kJ/molat 298.15K . Find the value of Kfor the reaction.

Short Answer

Step by step solution

Equilibrium constant

The value of K for the given reaction.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Inorganic Chemistry

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Study anywhere. Anytime. Across all devices.

For the reaction ${HCO}_{3}^{-} ⇌ H^{+} + " {CO}_{3}^{2 -}$ , $ΔG ° = + 59.0 kJ / mol$ at $298.15 K$ . Find the value of Kfor the reaction.