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Chapter 1: Q16P (page 22)

How many grams of methanol (CH3OH, FM 32.04) arecontained in0.100 L of 1.71 M aqueous methanol (i.e., 1.71 molCH3OH/L solution)?

Short Answer

Expert verified

The mass of the methanol is 5.48 g.

Step by step solution

01

Finding the mass of methanol

The mass of methanol can be calculated by using the formula of Molarity.

02

Given values

The volume= 0.100 L

The molar mass of CH3OH= 32.04 g/mol

The molarity of CH3OH= 1.71 M

03

Find the value of mass

Use the formula below:

Molarity=No.ofmolesVolumeinL

Whereas, the no. of moles=GivenmassMolarmass

Replace the given values:

1.71M=Givenmass32.041.100L

Given mass role="math" localid="1663307729434" =1.71×32.04×0.100=5.48g

Thus, the mass of methanol is 5.48 g.

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