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Chapter 1: Q24P (page 23)

An aqueous solution containing 20.0wt%KI has a density of1.168g/mL. Find the molality (m, not M) of the KI solution.

Short Answer

Expert verified

The molality of the KI solution is 1.51mol/kg

Step by step solution

01

Definition of molality.

The number of moles of solute in a solution equivalent to 1kgor 1000gof asolvent is known as its molality. The definition of molarity, on the other hand, is based on a certain volume of solution.

02

The molality of KI solution.

To begin, remember that molality, expressed as m1equals:

m1=molesofsolute(KI)massofsolvent(water)

It is given that the density of 1.168g/mLwhich is 1.168gof KI in 1mLof water, is 1168gin 1L

The total mass of the solute (KI) is equal to0.2×1168g=233.6g

The total mass of the solvent (water) is equal to 0.8×1168g=934.4g

Now, calculate the number of moles for KI:

nKI=mM=233.6g166g/mol=1.407mol

Now, calculate the molality m1

m1=nKImwater=1.407mol934.4g=1.51×10-3mol/g=1.51mol/kg

Hence, the molality is 1.51mol/kg

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