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Chapter 26: Q1TY (page 717)

Find the milliequivalents ofH+released if100mLof26.3mMNi2+were loaded on a cation exchange column in theH+form.

Short Answer

Expert verified

The milli equivalents of H+ that will be replaced by 100mL is26.3mMNi2+is5.26meq

Step by step solution

01

Concept used

Given that the volume and concentration of Ni2+is100mLand Ni2+is26.3mMcharge is +2

In the cation exchange column, calculate the milli equivalents of which will be replaced by 100mL of 26.3mMNi2+

02

Determine the meq of H+ released

Consider that the volume and concentration Ni2+of100mLand Ni2+is26.3mMcharge is +2 .

eq=n×molesofMn+=2×0.100L×0.0263mol/L=5.26meq

The supplied concentration, volume, and charge are put into the above equation to produce milli equivalents of H+ which will be replaced in the cation exchange column by 100mL of 26.3mM

In the cation exchange column, the milli equivalents of H+ that will be replaced by 100mL of 26.3mMNi2+are 5.26meq

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