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Chapter 26: Q32P (page 748)

d)Li+ has lower mobility than Na+. Explain why lithium phosphate can be used at higher electric field strength than sodium phosphate to generate the same current. What is the advantage of higher field strength for this separation?

Short Answer

Expert verified

d) The advantage of higher field strength for this separation is that it can cause the reduction in the migration time and the analysis wouldn't take so long.

Step by step solution

01

Define electric field.

It is a force on the charged particles in the field either attracting or repeling each other.

02

Explanation.

Considering that lower conductivity = higher electric field requirement in order to generate the same current, high field strength would cause the reduction in the migration time and the analysis wouldn't take so long.

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Most popular questions from this chapter

The observed behavior of benzyl alcohol (C6H5CH2OH) in capillary electrophoresis is given here. Draw a graph showing the number of plates versus the electric field and explain what happens as the field increases.

Fluorescent derivatives of amino acids separated by capillary zone electrophoresis had migration times with the following order: arginine (fastest) , phenylalanine , asparagine , serine , glycine(slowest). Explain why arginine has the shortest migration time.

What is deionized water? What kind of impurities are not removed by deionization?

Would molecular exclusion, affinity, or hydrophobic interaction chromatography be most appropriate for each of the following applications?

  1. Purifying and concentrating a crude mixture of an antibody.
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(a) A long thin molecule has a greater friction coefficient than a short fat molecule. Predict whether fumarate or maleate will have greater electrophoretic mobility.

(b) Electrophoresis is run with the injection end positive and the detection end negative. At pH 8.5, both anions have a charge of 22.The electroosmotic fl ow from the positive terminal to the negative terminal is greater than the electrophoretic flow, so these two anions have a net migration from the positive to the negative end of the capillary in electrophoresis. From your answer to part (a), predict the order of elution of these two species. (c)At pH 4.0, both anions have a charge close to 21, and the electroosmotic fl ow is weak. Therefore electrophoresis is run with the injection end negative and the detection end positive. The anions migrate from the negative end of the capillary to the positive end.Predict the order of elution.
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