Chapter 26: Q45P (page 750)

Suppose that the electroosmotic mobility of a solution is $+ 1.61 \times 10^{- 7} m^{2} / (V \times s)$ ) How many plates are required to separate sulfate from bromide with a resolution of 2.0? Use Table 15-1 for mobilities and Equation 26-14 for resolution.

Short Answer

Expert verified

Plates that are required to separate sulfate from bromide with a resolution of 2.0 is $N = 2 \times 5^{10} plates$

Step by step solution

Plates that are required to separate sulfate from bromide with a resolution of 2.0

From Table 15-1 we will use the following:

$μ_{ep} ({SO}_{4}^{2 -}) = - 8.27 \times 10^{- 8} m / Vs μ_{app} = μ_{eo} = μ_{ep} μ_{app} = (16.1 \times 10^{- 8}) + {(- 8.27 \times 10^{- 8})}^{a} μ_{app} = 7.83 \times 10^{- 8} m^{2} / Vs μ_{ep} ({Br}^{-}) = - 8.13 \times 10^{- 8} m^{2} / Vs μ_{app} = μ_{eo} = μ_{ep} μ_{app} = (16.1 \times 10^{- 8}) + (- 8.13 \times 10^{- 8}) μ_{app} = 7.97 \times 10^{- 8} m^{2} / Vs$

Step 2:Calculate the average

$Next we will calculate the average μ and ∆ μ_{ep}$

$μ_{av} = \frac{(7.83 \times 10^{- 8}) + (7.97 \times 10^{- 8})}{2} μ_{av} = 7.90 \times 10^{- 8} m^{2} / Vs ∆ μ_{ep} = (8.27 \times 10^{- 8}) - (8.13 \times 10^{- 8}) ∆ μ_{ep} = 0.14 \times 10^{- 8} m^{2} / Vs$

Step 3:Equation 26-14 for resolution

Then we will use the Equation 26-14 for resolution:

$N = {(4 \times (Resolution) \frac{μ_{av}}{∆ μ_{ep}})}^{2} N = {(4 \times (2.0) \frac{7.90}{0.14})}^{2} N = 2 \times 10^{5} plates$

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Suppose that the electroosmotic mobility of a solution is $+ 1.61 \times 10^{- 7} m^{2} / (V \times s)$ ) How many plates are required to separate sulfate from bromide with a resolution of 2.0? Use Table 15-1 for mobilities and Equation 26-14 for resolution.

Short Answer

Step by step solution

Plates that are required to separate sulfate from bromide with a resolution of 2.0

Step 2:Calculate the average

Step 3:Equation 26-14 for resolution

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Suppose that the electroosmotic mobility of a solution is +1.61×10-7m2/(V×s)) How many plates are required to separate sulfate from bromide with a resolution of 2.0? Use Table 15-1 for mobilities and Equation 26-14 for resolution.

Short Answer

Step by step solution

Plates that are required to separate sulfate from bromide with a resolution of 2.0

Step 2:Calculate the average

Step 3:Equation 26-14 for resolution

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Nuclear Chemistry

Physical Chemistry

Organic Chemistry

Making Measurements

The Earths Atmosphere

Chemical Reactions

Study anywhere. Anytime. Across all devices.

Suppose that the electroosmotic mobility of a solution is $+ 1.61 \times 10^{- 7} m^{2} / (V \times s)$ ) How many plates are required to separate sulfate from bromide with a resolution of 2.0? Use Table 15-1 for mobilities and Equation 26-14 for resolution.