Find [Ca2+] in 0.10 M CaY2- at pH 8.00

Short Answer

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The concentration of [Ca2+] is 2.3×10-5Min 0.10 M CaY2- at pH 8.00.

Step by step solution

01

Introduction

The fraction of all free EDTA (in Y4- format) is expressed in terms of αY4-. It can be expressed as

αY4-=Y4-H6Y2++H5Y++H4Y+H3Y-+H2Y2-+HY3-+Y4-

From table 12-1 it was found that for, αY4-=4.2×10-3

From table 12-2 it was found that for CaY2-,Kf=1010.65

02

Determine the conditional formation constant

Kf'=αY4-KfKf'=4.2×10-3×1010.65=4.2×107.65

03

Determine concentration of [Ca2+]

Ca2++EDTACaY2-InitialConcentration000.1FinalConcentrationxx0.1-x

From the above ICE table we can write

CaY2-Ca2+EDTA=Kf'0.1-xx2=4.2×107.65x=2.3×10-5

Therefore, the concentration of [Ca2+] is 2.3×10-5M

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Most popular questions from this chapter

Give an example of the use of a masking agent

Spreadsheet equation for formation of the complexes ML and ML2.Consider the titration of metal M (initial concentration = CM, initial volume = VM) with ligand L (concentration = CL, volume added = VL), which can form 1:1 and 2 : 1 complexes:

M+L𝆏MLβ1=[ML][M][L]M+2L𝆏ML2β2=[ML2][M][L]2

Let αM be the fraction of metal in the form M, αML be the fraction in the form ML, and αML2be the fraction in the form ML2. Following the derivation in Section 12-5, you could show that these fractions are given by

role="math" localid="1667801924683" αM1=11+β1[L]+β2[L]2αML=β1[L]1+β1[L]+β2[L]2αML2=β2[L]21+β1[L]+β2[L]2

The concentrations of ML and ML2are

[ML]=αMLCMVMVM+VL[ML2]=αML2CMVMVM+VL

because CMVMVM+VLis the total concentration of all metal in the solution. The mass balance for ligand is

[L]+[ML]+2[ML2]=CMVMVM+VL

By substituting expressions for [ML] and [ML2] into the mass balance, show that the master equation for a titration of metal by ligand is

ϕ=CLVLVM+VM=αML+2αML2+LCM1-LCL

Consider the titration of 25.0 mL of 0.020 0 M MnSO4 with 0.010 0 M EDTA in a solution buffered to pH 8.00. Calculate pMn2+ at the following volumes of added EDTA and sketch the titration curve:

(a) 0 mL (b) 20.0 mL (c) 40.0 mL (d) 49.0 mL (e) 49.9 mL (f) 50.0 mL (g) 50.1 mL

(h) 55.0 mL (i) 60.0 mL

The sulfur content of insoluble sulfides that do not readily dissolve in acid can be measured by oxidation with Br2 to .25 Metal ions are then replaced with H+ by an ion-exchange column, and sulfate is precipitated as BaSO4 with a known excess of BaCl2. The excess Ba2+ is then titrated with EDTA to determine how much was present. (To make the indicator end point clearer, a small, known quantity of Zn2+ also is added. The EDTA titrates both the Ba2+ and the Zn2+.) Knowing the excess Ba2+, we can calculate how much sulfur was in the original material. To analyze the mineral sphalerite (ZnS, FM 97.46), 5.89 mg of powdered solid were suspended in a mixture of CCl4 and H2O containing 1.5 mmol Br2. After 1 h at 200 C and 2 h at 500 C, the powder dissolved and the solvent and excess Br2 were removed by heating. The residue was dissolved in 3 mL of water and passed through an ion-exchange column to replace Zn2+ with H+. Then 5.000 mL of 0.014 63 M BaCl2 were added to precipitate all sulfate as BaSO4. After the addition of 1.000 mL of 0.010 00 M ZnCl2 and 3 mL of ammonia buffer, pH 10, the excess Ba2+ and Zn2+ required 2.39 mL of 0.009 63 M EDTA to reach the Calmagite end point. Find the weight percent of sulfur in the sphalerite. What is the theoretical value?

List four methods for detecting the end point of an EDTA Titration

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