Pyrocatechol violet(Table 12-3) is to be used as a metal ion indicator in an EDTA titration. The procedure is as follows:

1. Add a known excess of EDTA to the unknown metal ion.

2. Adjust the pH with a suitable buffer.

3. Back-titrate the excess chelate with standard Al3+.

From the following available buffers, select the best buffer, and then state what color change will be observed at the end point. Explain your answer.

  1. pH 6–7 (ii) pH 7–8 (iii) pH 8–9 (iv) pH 9–10

Short Answer

Expert verified

From table 12-3 it can be identified that buffer solution of pH 6-7 is the most suitable one as in this range the color change occurs from yellow to blue while for the other pH ranges the color changes from violet to blue. Identifying change from yellow to blue is much easier than that of violet to blue. So (i) pH6-7 will be the best buffer to operate with.

Step by step solution

01

EDTA

EDTA, also known as ethylenediaminetetraacetic acid forms strong complexes with metal ions and plays a major role in quantitative analysis. In industries it is used as a metal binding agent and used in production of detergents, cleaning agents, food additives etc.

02

Reaction procedure

A titration reaction between pyrocatechol violet (a metal ion indicator) and EDTA follows the steps below;

For an unknown concentration of metal ion, a known excess of EDTA must be added. Then the pH must be adjusted using a suitable buffer. After that we need to back titrate the excess amount of chelate with standard solution of Al3+

03

Selection of best buffer

From table 12-3 it can be identified that buffer solution of pH 6-7 is the most suitable one as in this range the color change occurs from yellow to blue while for the other pH ranges the color changes from violet to blue. Identifying change from yellow to blue is much easier than that of violet to blue. So (i) pH6-7 will be the best buffer to operate with.

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Most popular questions from this chapter

Calculate pCu2+ at each of the following points in the titration of 50.00 mL of 0.001 00 M Cu2+ with 0.00100 M EDTA at pH 11.00 in a solution with [NH3] fixed at 1.00 M:

(a) 0 mL(b) 1.00 mL (c) 45.00 mL (d) 50.00 mL (e) 55.00 mL

Sulfide ion was determined by indirect titration with EDTA. To a solution containing 25.00 mL of 0.04332 M Cu(ClO4)2 plus 15 mL of 1 M acetate buffer (pH 4.5) were added 25.00 mL of unknown sulfide solution with vigorous stirring. The CuS precipitate was filtered and washed with hot water. Ammonia was added to the filtrate (which contained excess Cu2+) until the blue color of Cu(NH3)42+ was observed. Titration of the filtrate with 0.039 27 M EDTA required 12.11 mL to reach the murexide end point. Calculate the molarity of sulfide in the unknown.

If back titration required 13.00 mL Zn2+, what was the original concentration of Ni2+?

A 50.0-mL solution containing Ni2+ and Zn2+ was treatedwith 25.0 mL of 0.045 2 M EDTA to bind all the metal. The excess unreacted EDTA required 12.4 mL of 0.012 3 M Mg2+ for complete reaction. An excess of the reagent 2,3-dimercapto-1-propanol was then added to displace the EDTA from zinc. Another 29.2 mL of Mg2+ were required for reaction with the liberated EDTA. Calculate the molarity of Ni2+ and Zn2+ in the original solution

Consider the titration of 25.0 mL of 0.020 0 M MnSO4 with 0.010 0 M EDTA in a solution buffered to pH 8.00. Calculate pMn2+ at the following volumes of added EDTA and sketch the titration curve:

(a) 0 mL (b) 20.0 mL (c) 40.0 mL (d) 49.0 mL (e) 49.9 mL (f) 50.0 mL (g) 50.1 mL

(h) 55.0 mL (i) 60.0 mL

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