Chapter 12: Q29P (page 285)
Give an example of the use of a masking agent
Short Answer
The Mg2+ in a solution of Mg2+ and Fe3+ must be titrated by EDTA. If the Fe3+ is masked with to form which does not react with EDTA.
Chapter 12: Q29P (page 285)
Give an example of the use of a masking agent
The Mg2+ in a solution of Mg2+ and Fe3+ must be titrated by EDTA. If the Fe3+ is masked with to form which does not react with EDTA.
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Get started for freeTitration of M with L to form ML and ML2. Use theequation from Problem 12-21, where M is Cu2+ and L is acetate.Consider adding 0.500 M acetate to 10.00 mL of 0.050 0 M Cu2+ atpH 7.00 (so that all ligand is present as , not CH3CO2H).Formation constants forCu(CH3CO2)+ and Cu(CH3CO2)2 aregiven in Appendix I. Construct a spreadsheet in which the inputis pL and the output is [L], VL, [M], [ML], and [ML2]. Prepare agraph showing concentrations of L, M, ML, and ML2as VL rangesfrom 0 to 3 mL
Pyrocatechol violet(Table 12-3) is to be used as a metal ion indicator in an EDTA titration. The procedure is as follows:
1. Add a known excess of EDTA to the unknown metal ion.
2. Adjust the pH with a suitable buffer.
3. Back-titrate the excess chelate with standard Al3+.
From the following available buffers, select the best buffer, and then state what color change will be observed at the end point. Explain your answer.
Calculate pCu2+ at each of the following points in the titration of 50.00 mL of 0.001 00 M Cu2+ with 0.00100 M EDTA at pH 11.00 in a solution with [NH3] fixed at 1.00 M:
(a) 0 mL(b) 1.00 mL (c) 45.00 mL (d) 50.00 mL (e) 55.00 mL
Consider the titration of 25.0 mL of 0.020 0 M MnSO4 with 0.010 0 M EDTA in a solution buffered to pH 8.00. Calculate pMn2+ at the following volumes of added EDTA and sketch the titration curve:
(a) 0 mL (b) 20.0 mL (c) 40.0 mL (d) 49.0 mL (e) 49.9 mL (f) 50.0 mL (g) 50.1 mL (h) 55.0 mL (i) 60.0 mL
A 1.000-mL sample of unknown containing Co2+ and Ni2+ was treated with 25.00 mL of 0.038 72 M EDTA. Back titration with 0.021 27 M Zn2+ at pH 5 required 23.54 mL to reach the xylenol orange end point. A 2.000-mL sample of unknown was passed through an ion-exchange column that retards Co2+ more than Ni2+. The Ni2+ that passed through the column was treated with 25.00 mL of 0.038 72 M EDTA and required 25.63 mL of 0.021 27 M Zn2+ for back titration. The Co2+ emerged from the column later. It, too, was treated with 25.00 mL of 0.038 72 M EDTA. How many milliliters of 0.021 27 M Zn2+ will be required for back titration?
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