Find pZn2+ after adding 30.0 and 51.0 mL of EDTA.

Short Answer

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After adding 30 mL EDTA pZn+ is 8.35 and after adding 51 mL of EDTA pZn+ is 10.3

Step by step solution

01

Information given

Consider the titration of 50.0 mL of 1.00 × 10-3 M Zn2+ with 1.00 × 10-3 M EDTA at

pH 10.00 in the presence of 0.10 M NH3. The equivalence point is at 50.0 mL

Equations and data obtained in order to proceed for calculation are as follows

αZn2+=11+β1L+β2L2+β3L3+β4L4

From Eq 12-17αZn2+=1.8×10-5

Kf=1016.5AtpH10αY4-=0.3(Table12-1)

02

Determine equilibrium constant

K4'=αZn2+×αy4-×Kf=1.8×10-5×0.3×1016.5=1.7×1011

Equivalence point=50 mL

03

Determine the value of pZn2+ after adding 30 mL of EDTA

Before the equivalence point

The concentration of the remaining productcan be calculated using the following equation

=Fraction remaining × Initial concentration × Dilution factor

If 30 mL solution is added then the reaction will be 30/50 completed as the equivalence point is at 50 mL. Then the metal concentration will be

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Most popular questions from this chapter

Spreadsheet equation for formation of the complexes ML and ML2.Consider the titration of metal M (initial concentration = CM, initial volume = VM) with ligand L (concentration = CL, volume added = VL), which can form 1:1 and 2 : 1 complexes:

M+L𝆏MLβ1=[ML][M][L]M+2L𝆏ML2β2=[ML2][M][L]2

Let αM be the fraction of metal in the form M, αML be the fraction in the form ML, and αML2be the fraction in the form ML2. Following the derivation in Section 12-5, you could show that these fractions are given by

role="math" localid="1667801924683" αM1=11+β1[L]+β2[L]2αML=β1[L]1+β1[L]+β2[L]2αML2=β2[L]21+β1[L]+β2[L]2

The concentrations of ML and ML2are

[ML]=αMLCMVMVM+VL[ML2]=αML2CMVMVM+VL

because CMVMVM+VLis the total concentration of all metal in the solution. The mass balance for ligand is

[L]+[ML]+2[ML2]=CMVMVM+VL

By substituting expressions for [ML] and [ML2] into the mass balance, show that the master equation for a titration of metal by ligand is

ϕ=CLVLVM+VM=αML+2αML2+LCM1-LCL

According to Appendix I, Cu2+ forms two complexes with acetate:

Cu2++CH3CO2Cu(CH3CO2)+       β1(=K1)Cu2++2CH3CO2Cu(CH3CO2)2       β2

(a) Referring to Box 6-2, find K2 for the reaction

Cu(CH3CO2)++CH3CO2Cu(CH3CO2)2(aq)   K2

(b) Consider 1.00 L of solution prepared by mixing 1.00 × 10-4 mol Cu(ClO4)2 and 0.100 mol CH3CO2Na. Use Equation 12-16 to find the fraction of copper in the form Cu2+


Calculate pCu2+ at each of the following points in the titration of 50.00 mL of 0.001 00 M Cu2+ with 0.00100 M EDTA at pH 11.00 in a solution with [NH3] fixed at 1.00 M:

(a) 0 mL(b) 1.00 mL (c) 45.00 mL (d) 50.00 mL (e) 55.00 mL

Consider the titration of 25.0 mL of 0.020 0 M MnSO4 with 0.010 0 M EDTA in a solution buffered to pH 8.00. Calculate pMn2+ at the following volumes of added EDTA and sketch the titration curve:

(a) 0 mL (b) 20.0 mL (c) 40.0 mL (d) 49.0 mL (e) 49.9 mL (f) 50.0 mL (g) 50.1 mL(h) 55.0 mL (i) 60.0 mL

The sulfur content of insoluble sulfides that do not readily dissolve in acid can be measured by oxidation with Br2 to .25 Metal ions are then replaced with H+ by an ion-exchange column, and sulfate is precipitated as BaSO4 with a known excess of BaCl2. The excess Ba2+ is then titrated with EDTA to determine how much was present. (To make the indicator end point clearer, a small, known quantity of Zn2+ also is added. The EDTA titrates both the Ba2+ and the Zn2+.) Knowing the excess Ba2+, we can calculate how much sulfur was in the original material. To analyze the mineral sphalerite (ZnS, FM 97.46), 5.89 mg of powdered solid were suspended in a mixture of CCl4 and H2O containing 1.5 mmol Br2. After 1 h at 200 C and 2 h at 500 C, the powder dissolved and the solvent and excess Br2 were removed by heating. The residue was dissolved in 3 mL of water and passed through an ion-exchange column to replace Zn2+ with H+. Then 5.000 mL of 0.014 63 M BaCl2 were added to precipitate all sulfate as BaSO4. After the addition of 1.000 mL of 0.010 00 M ZnCl2 and 3 mL of ammonia buffer, pH 10, the excess Ba2+ and Zn2+ required 2.39 mL of 0.009 63 M EDTA to reach the Calmagite end point. Find the weight percent of sulfur in the sphalerite. What is the theoretical value?

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