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Chapter 3: Q9P (page 62)

Why do we use quotation marks around the word true in the statement that accuracy refers to how close a measured value is to the "true" value?

Short Answer

Expert verified

Because any measurement is subject to error, and some people must measure in order to obtain the "true" value, quotation marks are used around the term true in the statement that accuracy refers to how close a measured value is to the "true" value.

Because a "true" measurement must be taken by someone, and every measurement has some degree of error, true is surrounded by quotation marks.

Step by step solution

01

Definition of accuracy.

Observational error may be measured in two ways: accuracy and precision. Precision is defined as how near or far apart a set of measurements are from their real value, whilst accuracy is defined as how close or far apart the measurements are from each other.

02

Determine why do we use quotation mark.

Because there is error in any measurement and some must measure to acquire the "actual" value, quotation marks are used around the word true in the statement that accuracy refers to how near a measured value is to the "true" value.

True is surrounded by quotation marks because a "true" measurement must be taken by someone, and every measurement has some degree of inaccuracy.

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Most popular questions from this chapter

Write each answer with the correct number of significant figures.

(a)1.0+2.1+3.4+5.8=12.3000

(b) 106.9 - 31.4 = 75.5000

(c)107.868(2.113×102)+(5.623×103)=5519.568

(d)(26.14/37.62)×4.38=3.043413

(e(26.14/37.62×108)×(4.38×10-2)=3.043413×10-10

(f)(26.14/3.38)+4.2=4.5999

(g)log(3.98×104)=4.5999

(h)10-6.31=4.89779×10-7

Suppose that in a gravimetric analysis, you forget to dry the filter crucibles before collecting precipitate. After filtering the product, you dry the product and crucible thoroughly before weighing them. Is the apparent mass of product always high or always low? Is the error in mass systematic or random?

Controlling the appearance of a graph. Figure 3-3 requires gridlines to read buret corrections. In this exercise, you will format a graph so that it looks like Figure 3-3 . Follow the procedure in Section 2-11 to graph the data in the following table. For Excel 2007 or 2010, insert a Chart of the type Scatter with data points connected by straight lines. Delete the legend and title. With Chart Tools, Layout, Axis Titles, add labels for both axes. Click any number on the abscissa ( x axis) and go to Chart Tools, Format. In Format Selection, Axis Options, choose Minimum =0 , Maximum =50 , Major unit =10 , and Minor unit =1 . For Major tick mark type, select Outside. In Format Selection, Number, choose Number and set Decimal places =0. In a similar manner, set the ordinate ( y -axis) to run from -0.04 to +0.05 with a Major unit of 0.02 and a Minor unit of 0.01 and with Major tick marks Outside. To display gridlines, go to Chart Tools, Layout, and Gridlines. For Primary Horizontal Gridlines, select Major & Minor Gridlines. For Primary Vertical Gridlines, select Major & Minor Gridlines. To move axis labels from the middle of the chart to the bottom, click a number on the y axis (not the x axis) and select Chart Tools, Layout, Format Selection. In Axis Options, choose Horizontal axis crosses Axis value and type in -0.04 . Close the Format Axis window and your graph should look like Figure 3-3 .

Write each answer with a reasonable number of figures. Find the absolute and percent relative uncertainty for each answer.

(a)[12.41(±0.09)÷4.16(±0.01)]×7.0682(±0.0004)=?

(b)[3.26(±0.10)×8.47(±0.05)]-0.18(±0.06)=?(c)6.843(±0.008)×104÷[2.09(±0.04)-1.63(±0.01)]=?(d)3.24±0.08=?(e)(3.24±0.08)4=?(f)log(3.24±0.08)=?(g)103.24±0.08=?

Rewrite the number 3.123 56 (±0.167 89%) in the forms (a) number (± absolute uncertainty) and (b) number (± percent relative uncertainty) with an appropriate number of digits.
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