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Chapter 18: Q19P (page 457)

If a sample for spectrophotometric analysis is placed in a 10 - cmcell, the absorbance will be 10times greater than the absorbance in a 1 - cmcell. Will the absorbance of the reagent-blank solution also be increased by a factor of 10?

Short Answer

Expert verified

Yes, the absorbance of the reagent-blank solution also be increased by a factor of 10.

Step by step solution

01

Define Reagent Blank Solution

A reagent blank is a mixture of any solvent and reagent that would be presented to the detector for analysis of a test sample and is analysed to determine if it contributes to the measurement signal.

02

Reaction of Solution

Yes, the absorbance of the reagent-blank solution also be increased by a factor of 10.

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Most popular questions from this chapter

Characteristic orange light produced by sodium in a flame is due to an intense emission called the sodium D line, which actually a doublet, with wavelength (measured in vacuum) of 589.157 88 and 589.755 37 nm. The index of refraction of air at a wavelength near 589 nm is 1.000 292 6. Calculate the frequency, wavelength, and wavenumber of each component of the D line, measured in air.

You have been sent to India to investigate the occurrence ofgoiter disease attributed to iodine deficiency. As part of your investigation, you must make field measurements of traces of iodide I2in groundwater. The procedure is to I2 into an intensely colored complex with the dye brilliant green inthe organic solvent toluene.

(a)A 3.15×10-6Msolution of the colored complex exhibited an absorbance of 0.267 at 635nmin a 1.00 - cm cuvet. A blank solution made from distilled water in place of groundwater had an absorbance of 0.019 . Find the molar absorptivity of the coloredcomplex.

(b) The absorbance of an unknown solution prepared from groundwater was0.175. Find the concentration of the unknown.

Preparing standards for a calibration curve.

(a) How much ferrous ammonium sulfate(FeNH42SO42⋅6H2OFM392.15)should be dissolved in a 500mL volumetric flask withto obtain a stock solution with1000μgFe/mL?

(b) When making stock solution (a), you weighed out 3.627 g of reagent. What is the Fe concentration in?

(c) How would you prepare 250mL of standard containing containing ~1,2,3,4,5,6,7,8and10in0.1MH2SO4infrom stock solution (b) using only 5- and 10-mL Class A pipets, only 250mL volumetric flasks, and only two consecutive dilutions of the stock solution? For example, to prepare a solution with ~4μgFe/mL,, you could first dilute 15mL(=10+5mL) of stock solution up to 250 mL mLto get~(1525)(1000μgFFe/mL)=∼60μgFe/mL Then dilute 15mL of the new solution up to 250 mL again to get~(15250)(60μgFe/mL)=∼3.6μgFe/mL

Dilution by mass is more accurate than dilution by volume. A stocksolution contains 1.044 g Fe/kg solution in 0.48 M HCl. How many μgFe/gsolution are in a solution made by mixing 2.145 g stock solution with 243.27 g 0.1 M HCl?

The absorbance of a 2.31×10-5M solution of a compound is 0.822 at a wavelength of 266nm in a 1.00-cm cell. Calculate the molar absorptivity at 266nm.
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