Chapter 18: Q1TY (page 460)
What is the wavelength, wavenumber, and name of radiation with an energy of 100 kJ/mol?
Short Answer
The wavelength is
The wavenumber is
The name of radiation is Infrared radiation.
Chapter 18: Q1TY (page 460)
What is the wavelength, wavenumber, and name of radiation with an energy of 100 kJ/mol?
The wavelength is
The wavenumber is
The name of radiation is Infrared radiation.
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18-10. Color and absorption spectra. Color Plate 17 shows coalored solutions and their spectra. From Table 18-1, predict the color of each solution from the wavelength of maximum absorption. Do observed colors agree with predicted colors?
Characteristic orange light produced by sodium in a flame is due to an intense emission called the sodium D line, which actually a doublet, with wavelength (measured in vacuum) of 589.157 88 and 589.755 37 nm. The index of refraction of air at a wavelength near 589 nm is 1.000 292 6. Calculate the frequency, wavelength, and wavenumber of each component of the D line, measured in air.
Gold nanoparticles (Figure 17-31) can be titrated with the oxidizing agent TCNQ in the presence of excess ofto oxidize in deaerated toluene. Gold atoms in the interior of the particle are Au(0) . Gold atoms bound to - (dodecanethiol) ligands on the surface of the particle are Au(I) and are not titrated.
The table gives the absorbance at $856 0.700 mL of in toluene is titrated with gold nanoparticles (1.43 g/Lin toluene) from a microsyringe with a Teflon-coated needle. Absorbance in the table has already been corrected for dilution.
(a) Make a graph of absorbance versus volume of titrant and estimate the equivalence point. Calculate the Au(0) in 1.00 g of nanoparticles.
(b) From other analyses of similarly prepared nanoparticles, it is estimated that 25 % of the mass of the particle is dodecanethiol ligand. Calculate mmol of localid="1667559229564" in 1.00 g of nanoparticles.
(c) The Au(I) content of 1.00 g of nanoparticles should be 1.00 mass of Au(0) - mass of . Calculate the micromoles of Au(I) in 1.00 g of nanoparticles and the mole ratio Au(I) :. In principle, this ratio should be 1: 1. The difference is most likely because was not measured for this specific nanoparticle preparation.
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