You have been sent to India to investigate the occurrence ofgoiter disease attributed to iodine deficiency. As part of your investigation, you must make field measurements of traces of iodide I2in groundwater. The procedure is to I2 into an intensely colored complex with the dye brilliant green inthe organic solvent toluene.

(a)A 3.15×10-6Msolution of the colored complex exhibited an absorbance of 0.267 at 635nmin a 1.00 - cm cuvet. A blank solution made from distilled water in place of groundwater had an absorbance of 0.019 . Find the molar absorptivity of the coloredcomplex.

(b) The absorbance of an unknown solution prepared from groundwater was0.175. Find the concentration of the unknown.

Short Answer

Expert verified
  1. The molar absorptivity of the colored complexo˙=78730M-1cm-1
  2. The concentration of the unknown c=1.98.10-6M

Step by step solution

01

Define Iodine Deficiency

Iodine deficiency is a lack of the trace element iodine, an essential nutrient in thediet.

02

Calculation of Concentration

A = 0.175 - 0.019 = 0.156

Concentration of unknown

c=Ab.o˙=0.15678730M-1c-1.1cmc=1.98.10-6M

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Gold nanoparticles (Figure 17-31) can be titrated with the oxidizing agent TCNQ in the presence of excess ofBr2-to oxidize Au(0)"toAuBr2-in deaerated toluene. Gold atoms in the interior of the particle are Au(0) . Gold atoms bound to C12H25S- (dodecanethiol) ligands on the surface of the particle are Au(I) and are not titrated.

The table gives the absorbance at $856 0.700 mL of 1.00×10-4MTCNQ+0.05M(C8H17)4N+Br-in toluene is titrated with gold nanoparticles (1.43 g/Lin toluene) from a microsyringe with a Teflon-coated needle. Absorbance in the table has already been corrected for dilution.

(a) Make a graph of absorbance versus volume of titrant and estimate the equivalence point. Calculate the Au(0) in 1.00 g of nanoparticles.

(b) From other analyses of similarly prepared nanoparticles, it is estimated that 25 % of the mass of the particle is dodecanethiol ligand. Calculate mmol of localid="1667559229564" C12H25Sin 1.00 g of nanoparticles.

(c) The Au(I) content of 1.00 g of nanoparticles should be 1.00 mass of Au(0) - mass of C12H25S. Calculate the micromoles of Au(I) in 1.00 g of nanoparticles and the mole ratio Au(I) :. In principle, this ratio should be 1: 1. The difference is most likely because C12H25Swas not measured for this specific nanoparticle preparation.

The transmittance of a 0.010 M solution of a compound in a 0.100-cm-path length cell is .T=8.23%Find the absorbance (A) and the molar absorptive (ε).

Semi-xylenol orange is a yellow compound at pH 5.9but turns red when it reacts with Pb2+. A 2.025 - mLsample of semixylenol orange at pH 5.9was titrated with7.515×10-4MPb(NO3)2with the following results:

Total role="math" localid="1663647483742" μLPb2+added

Absorbance at 490nmwavelength

Total μLPb2+added

Absorbance at490nmwavelength

0.0

6.0

12.0

18.0

24.0

30.0

36.0

0.227

0.256

0.286

0.316

0.345

0.370

0.399

42.0

48.0

54.0

60.0

70.0

80.0


0.425

0.445

0.448

0.449

0.450

0.447


Make a graph of absorbance versus microliters of Pb2+added. Be sure to correct the absorbances for dilution. Corrected absorbance is what would be observed if the volume were not changed from its initial value of 2.025Ml. Assuming that the reaction of semi orange with Pb2+has a 1 : 1stoichiometry, find the molarity of semi-xylenol orange in the original solution.

18-8: What is an absorption spectrum?

18-26. A 2.00mL solution of apotransferrin was titrated as illustrated in Figure 18-11. It required 163L of 1.43 mM ferric nitrilotriacetate to reach the end point.

(a) Why does the slope of the absorbance versus volume graph change abruptly at the equivalence point?

(b) How many moles of Fe(III) (= ferric nitrilotriacetate) were required to reach the end point?

(c) Each apotransferrin molecule binds two ferric ions. Find the molar concentration of apotransferrin in the 2.00mL solution.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free