Chapter 18: Q2TY (page 437)

The transmittance of a 0.010 M solution of a compound in a 0.100-cm-path length cell is . $T = 8.23 %$ Find the absorbance (A) and the molar absorptive (ε).

Short Answer

Expert verified

The value of absorbance is $\approx 1.08$

The value of molar absorptive is $1.08 x 1 10^{3} M^{- 1} {cm}^{- 1}$

Step by step solution

Calculate absorbance:

Equation for absorbance is

$A = - \log T$ →(1)

To find transmittance the equation is $T = \frac{% T}{100 %}$

Substitute $8.23 % for %$ in above equation,

$T = \frac{% T}{100 %} = 0.0823$

Substitute the value of transmittance in (1),

$A = - \log T A = - \log (0.0823) \approx 1.08$

The value of absorbance is $\approx 1.08$

Calculate molar absorptive:

Equation to calculate ε is,

$ε = \frac{A}{bc}$ →(2)

Given,

$c = 0.010 M b = 0.100 cm A = 1.08$

Substitute in equation (2),

$ε = \frac{1.08}{(0.0100 cm) (0.010 M)} ε = 1.08 x 10^{3} M^{- 1} {cm}^{- 1}$

The value of molar absorptive is $1.08 x 10^{3} M^{- 1} {cm}^{- 1}$

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The transmittance of a 0.010 M solution of a compound in a 0.100-cm-path length cell is . $T = 8.23 %$ Find the absorbance (A) and the molar absorptive (ε).

Short Answer

Step by step solution

Calculate absorbance:

Calculate molar absorptive:

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The transmittance of a 0.010 M solution of a compound in a 0.100-cm-path length cell is .T=8.23%Find the absorbance (A) and the molar absorptive (ε).

Short Answer

Step by step solution

Calculate absorbance:

Calculate molar absorptive:

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Making Measurements

Nuclear Chemistry

Chemistry Branches

The Earths Atmosphere

Organic Chemistry

Chemical Analysis

Study anywhere. Anytime. Across all devices.

The transmittance of a 0.010 M solution of a compound in a 0.100-cm-path length cell is . $T = 8.23 %$ Find the absorbance (A) and the molar absorptive (ε).