Explain what is displayed in a reconstructed total ion chromatogram, in selected ion monitoring, and in selected reaction monitoring. Which technique is most selective and which is least selective and why?

Short Answer

Expert verified

Throughout a chromatography experiment a reconstructed total ion chromatogram which is above a standard value of m/z is developed by addition of all ion intensities in each mass spectrum at each time interval.

In case of selected ion monitoring intensities (one or a few m/z values) are plotted versus elution time. The species with ion at which m/z values are detected, therefore the selectivity is much higher than that of reconstructured total ion chromatogram.

For selected reaction monitoring from the first mass separator one ion is passed through a collision cell. There it breaks into different products which are separated by a second mass separator. The intensities of the generated products are a function of time.

The selected reaction monitoring is the most selective whereas a reconstructed total ion chromatogram is the least selective. This technique is too selective that it can change a poor chromatographic separation into a highly specific determination of one compound with no interference.

Step by step solution

01

Reconstructed total ion chromatogram

Throughout a chromatography experiment a reconstructed total ion chromatogram which is above a standard value of m/z is developed by addition of all ion intensities in each mass spectrum at each time interval. This process does not have any selectivity and responds to everything eluted from the column.

02

Selected ion monitoring

In case of selected ion monitoring intensities (one or a few m/z values) are plotted versus elution time. The species with ion at which m/z values are detected, therefore the selectivity is much higher than that of reconstructured total ion chromatogram. If the entire spectrum were scanned, ions are collected at every m/z for a longer time than it is actually allowed. As a result, the signal to noise ratio increases.

03

Selected reaction monitoring

For selected reaction monitoring from the first mass separator one ion is passed through a collision cell. There it breaks into different products which are separated by a second mass separator. The intensities of the generated products are a function of time.

04

Selective technology

The selected reaction monitoring is the most selective whereas a reconstructed total ion chromatogram is the least selective. This technique is too selective that it can change a poor chromatographic separation into a highly specific determination of one compound with no interference

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Describe how retention time of butanol on a poly (ethylene glycol) column will change with increasing temperature. Use the retention time for butanol in Figure 24-9b as the starting point.

Efficiency of solid-phase microextraction. Equation24-9gives the mass of analyte extracted into a solid-phase microextraction fiber as a function of the partition coefficient between the fiber coating and the solution.

(a) A commercial fiber with a100-μm-thickcoating has a film volume of6.9×10-4mL. Suppose that the initial concentration of analyte in solution is

c0=0.10μg/mL(100ppb).Use a spreadsheet to prepare a graph showing the mass of analyte extracted into the fiber as a function of solution volume for partition coefficients of 10000,5000,1000and100and. Let the solution volume vary from 0to100mL.

(b) Evaluate the limit of Equation24-9asVr gets big relative to KVf. Does the extracted mass in your graph approach this limit?

(c) What percentage of the analyte fromof solution is extracted into the fiber when and whenK=100andwhenk=10000?

Astandard solution containing 6.3×10-8Miodoacetone and 2.0×10-7Mp-dichlorobenzene (an internal standard) gave peak areas of 395 and 787, respectively, in a gas chromatogram. A 3.00-mlunknown solution of iodoacetone was treated with 0.100mLof 1.6×10-5Mp-dichlorobenzene and the mixture was diluted to. Gas chromatography gave peak areas of 633 and 520 for iodoacetone and p-dichlorobenzene, respectively. Find the concentration of iodoacetone in the 3.00mLof original unknown.

(a) Explain how solid phase microextraction works. Why is cold trapping necessary during injection with this technique? Is all the analyte in an unknown extracted into the fiber in solid phase microextraction?

(b) Explain the differences between stir-bar sportive extraction and solid-phase microextraction. Which is more sensitive and why?

(a) What are the advantages and disadvantages of temperature programming in gas chromatography?

(b) What is the advantage of pressure programming?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free