(a) Find the limit of the square-root term ask0

(unretained solute) and as k(infinitely retained solute).

(b) If the column radius is 0.10mmfindHminfor the two cases in (a).

(c) What is the maximum number of theoretical plates in a 50 -m-long column with a 0.10-mm radius if k=5.0 ?

(d) The phase ratio is defined as the volume of the mobile phase divided by the volume of the stationary phase (β=Vm/Vs)Derive the relationship between βand the thickness of the stationary phase in a wall-coated column (df)and the inside radius of the column

(e) Find kif K=1000,df=0.20μm, and r=0.10 mm.

Short Answer

Expert verified

(a)The square-foot term as k0is 0.58 and the square-root term's limit as kis 1.9.

(b) role="math" localid="1665028364433" Hmin:k0is0.058mmHmin:kis0.19mm

(c) The maximum number of theoretical plates in 50m long column with 0.10 mm radius for k=5.0 is found to be 3.0×105

(d) The relation is derived as β=rdf.

(e)The value of k=4.0.

Step by step solution

01

Concept used

Theoretical gas chromatography performance. The greatest attainable column efficiency improves when the inside radius of an open tubular column is reduced, while sample capacity declines. The lowest theoretical plate height for a thin stationary phase that quickly equilibrates with analyte is given by

Hminr=1+6k+11k23(1+k)2

Where r is the column's inside radius and k is the retention factor.

02

Find the limit of the square-root term as k→0 (unretained solute) and as k→∞ (infinitely retained solute).

(a)

It was necessary to compute the square-root term's limit k0,k.

The square-root term limit as k0is 0.58.

The square-root term's limit as kis 1.9

As k0,

Hminr=13Hminr=0.58

As K,

Hminr=1+6k+11k231+k2Hminr=11k23k2Hminr=113Hminr=1.9

Thus, The square-foot term as k0is 0.58 and the square-root term's limit as kis 1.9.

03

Step 3: If the column radius is 0.10 mm find Hmin for the two cases in (a)

(b)

Calculate for k0,

Hminr=13Hminr=0.58Hmin=0.58rHmin=0.058mm

As k,

Hminr=1+6k+11k231+k2Hminr=11k23k2Hminr=113Hminr=1.9Hmin=1.9r

Therefore,

Hmink0is0.058mmHminkis0.19mm

04

If k=5.0, how many theoretical plates can fit in a 50-m-long column with a 0.10 -mm radius?

(c)

The maximum number of theoretical plates in 0.50m long column with 0.10 mm radius fik=5.0has to be calculated.

For k =5 ,

Hess=1.6MrHmen=0.168mm

The number of plates is calculated as,

Number of plates =3.0×105

The maximum number of theoretical plates in 50 m long column with 0.10mm radius for k=5.0 is found to be3.0×105.

05

Calculate the relationship between  and the thickness of the stationary phase in a wall-coated column  as well as the column's inside radius  

(d)

The dimensionless phase ratio is the volume of the mobile phase divided by the volume of the stationary phase. The phase ratio is computed using the formula:

β=rdf

Where, β=phase ratio

r = radius of column

df thickness of stationary phase time

As the thickness of the stationary phase decreases, βlowers, increasing the sample's retention duration and capacity.

06

Find  ,  

(e)

The value of k has to be calculated if K=1000.d1=0.20μm,r=0has to be calculated.

k=Kyivm

where, VS=volume of stationary phase

Vm= volume of mobile phase

For length of column L,

Volume of mobile phase=πr2l

Volume of stationary phase=2πrtl

Substitute these values in equation of k,

k=2πr|πr2|k=2tkrk=20.2μm.1000100μmk=4

Therefore, the value of k=4.0.

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