(a) What are the characteristics of an ideal carrier gas?

(b) Why do H2 and He allow more rapid linear velocities in gas chromatography thanN2 does, without loss of column efficiency (Figure 24-11)?

Short Answer

Expert verified

(a.) the carrier gas should have high quality because impurities can damage the stationary phase

(b.)H=A+Bux+Cux(

Step by step solution

01

To the characteristics of an ideal carrier gas

(a)

One characteristic of an ideal carrier gas is that it must have high optimal velocity to achieve good separation between compounds being analyzed. The carrier gas must also have a high diffusion coefficient so that solutes can diffuse more rapidly and thus result to a better resolution. The velocities of the carrier gas should also be 1.5-2 times greater than the optimum velocity at the minimum of the van Deemter curve, to provide maximum efficiency per unit time. Furthermore, the carrier gas should have high quality because impurities can damage the stationary phase

02

Step 2:H2and He allow more rapid linear velocities in gas chromatography than N2does, without loss of column efficiency (Figure 24-11)

(b)

H2and He allow more rapid linear velocities in gas chromatography than N2without loss of column efficiency, because solutes diffuse more rapidly through H2 than through role="math" localid="1654769938173" N2In the van Deemter equation, a small value of the mass transfer term (CUx) results to a solute with faster diffusion between phases.

H=A+Bux+Cux

where:

-H=plateheight-ux+linearvelocity-A,B,andC=constantsforagivencolumnandstationaryphase

For a thin stationary phase(^0.5μm), the mass transfer is dominated by slow diffusion through the mobile phase (Cm) than through the stationary phase(Cs).

That is,Cs<<Cm.

03

Step 3The expressions for CmareCm are shown below:

CM=1+6k+11K224(k+1)2×r2DmCs=2K3(K+12×d2Ds

where:

.k=retentionfactor.r=columnradius.d=thicknessofstationaryphase.Dm=diffusioncoefficientofsolutienmobilephase.Ds=diffusioncoefficientofsolutienstationaryphase

For a given column with fixed values of r and k, the only variable that can affect the rate of mass transfer in the mobile phase is the diffusion coefficient. Comparing the diffusion coefficients of the three gases, they follow the order:H2>H>N2.

Thus,role="math" localid="1654773241068" H2andH provide ease of diffusion for solutes.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) The term that is 0 for an open tubular column has to be explained with the reason.(b) The value of B must be stated in terms of a physical property that can be measured. (c) The value ofCmust be represented in terms of a physical attribute that can be measured. (d)The minimum plate height must be expressed in terms of quantifiable physical amounts of B and C.

(a) Why is it illogical to use a thin stationary phase (0.2 µm) in a wide-bore (0.53-mm) open tubular column?

(b) Consider a narrow-bore (0.25 mm diameter), thin-film (0.10 µm) column with 5 000 plates per meter. Consider also a wide-bore (0.53 mm diameter), thick-film (5.0 µm) column with 1500 plates per meter. The density of stationary phase is approximately 1.0 g/mL. What mass of stationary phase is in each column in a length equivalent to one theoretical plate? How many nanograms of analyte can be injected into each column if the mass of analyte is not to exceed 1.0% of the mass of stationary phase in one theoretical plate?

This problem reviews concepts from Chapter 23 using

Figure 24-15.

(a) Calculate the retention factor for peak 11 given tm 5 6.7 min.

(b) Calculate the number of theoretical plates (N in Equation 23-31)

and the plate height (H) for peak 11.

(c) Find the resolution (Equation 23-23) between peaks 16 and 17.

The gasoline additive methyl t-butyl ether (MTBE) has been leaking into groundwater ever since its introduction in the. MTBE can be measured at parts per billion levels by solid-phase microextraction from groundwater to which 25 % (wt/vol) NaCl has been added (salting out, Problem 8-9). After microextraction, analytes are thermally desorbed from the fiber in the port of a gas chromatograph. The figure on the next page shows a reconstructed total ion chromatogram and selected ion monitoring of substances desorbed from the extraction fiber.

(a) What is the purpose of adding NaCl prior to extraction?

(b) What nominal mass is being observed in selected ion monitoring? Why are only three peaks observed?

(c) Here is a list of major ions above m/z50 in the mass spectra. The base (tallest) peak is marked by an asterisk. Given that MTBE and TAME have an intense peak at m/z,73 and there is no significant peak at m/z,73 for ETBE, suggest a structure for m/z,73. Suggest structures for all ions listed in the table.

Efficiency of solid-phase microextraction. Equation24-9gives the mass of analyte extracted into a solid-phase microextraction fiber as a function of the partition coefficient between the fiber coating and the solution.

(a) A commercial fiber with a100-μm-thickcoating has a film volume of6.9×10-4mL. Suppose that the initial concentration of analyte in solution is

c0=0.10μg/mL(100ppb).Use a spreadsheet to prepare a graph showing the mass of analyte extracted into the fiber as a function of solution volume for partition coefficients of 10000,5000,1000and100and. Let the solution volume vary from 0to100mL.

(b) Evaluate the limit of Equation24-9asVr gets big relative to KVf. Does the extracted mass in your graph approach this limit?

(c) What percentage of the analyte fromof solution is extracted into the fiber when and whenK=100andwhenk=10000?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free