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Chapter 27: Q10P (page 767)

A 50.00-mL solution containingwas treated with excess AgNo3 to precipitate 0.2146 g of AgBr (FM 187.772). What was the molarity of NaBr in the solution?

Short Answer

Expert verified

The Molarity of NaBr in a solution is [NaBr]=0.02286M.

Step by step solution

01

calculate the moles of AgBr: 

In this task we have a 50 mL solution that contains NaBr treated with excess AgNO3in order to precipitate 0.2146 g of AgBr (FM = 187.772). Here we will calculate the molarity of NaBr in the solution.

Consider this reaction:

NaBr+AgNO3→AgBr+NaNO3

From the above reaction we can see that n(AgBr)=n(NaBr).

Calculate the moles of AgBr:

n(AgBr)=mMn(AgBr)=0.2416g187.772g/moln(AgBr)=1.1429×10-3mol

02

Calculate the molarity of NaBr:

[NaBr]=nV[NaBr]=1.1429×10-3mol50×10-3L[NaBr]=0.02286M

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Explain what is done in thermogravimetric analysis.

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