Microporous silica particles with a density of2.2g/mLand a diameter10μmof have a measured surface area of calculated the surface area of the300m2spherical silica as if it were simply solid particles what does this calculation tell you about the shape or porosity of the particles.

Short Answer

Expert verified

Microporous silica particles with a density calculation tell you about the shape or porosity of the particles.

First we calculate volume of sphere:

v=43.πr3v=43.π5.10-4cm3p=0.27m2

Step by step solution

01

definition of volume

The amount of three-dimensional space enclosed by a closed surface is expressed as a scalar quantity.

First we calculate volume of sphere:

v=43.πr3v=43.π5.10-4cm3p=5.24.10-4cm3

Then we calculate mass of one sphere:

m=ρ.vm=2.2g/mL.5.24.10-10mLm=1.15.10-9g

So, the number of particles in 1 g is:

role="math" localid="1654843608416" N=1g1.10.10-9gN=8.7.108

02

Step 2:surface one particle

The surface of one particle is:

p=4.πr2p=4.π5.10-6m2p=3.14.10-10m2

Now we calculate surface of particles:

p=3.10.10-10m2.8.7.102p=0.27m2

The measured surface area is 300m2, so the particles have irregular shapes and they are porous.

Hence,

p=0.27m2

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