what are criteria for an adequate isocratic chromatographic separation?

Short Answer

Expert verified

Criteria for an adequate isocratic chromatographic separation

If k is too small. The first peak must be distorted by the solvent front. If k is too great, the separation takes too long.

Step by step solution

01

definition of criteria adequate isocratic chromatographic separation

The criteria for an adequate isocratic chromatographic separation is K for all peaks must be in the range.0.5-20 If k is too small.

K for all peaks must be in the range 0.5-20.

If k is too small.

The first peak must be distorted by the solvent front.

If k is too great, the separation takes too long.

The minimum resolution of 1.5between the two closest peaks is desired.

ruggedness, a resolution of2 is desirable.

02

The separation

The pressure must be below15MPa150barso that it prolongs the life of the pump, valves, seals, and autosampler all peaks should be symmetric, with an asymmetry factor B/A in the range0.9-1.5.

Hence,

If k is too small. The first peak must be distorted by the solvent front. If k is too great, the separation takes too long.

The minimum resolution of 1.5between the two closest peaks is desired.ruggedness, a resolution of 2is desirable.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) When you try separating an unknown mixture byreversed-phase chromatography with 48%acetonitrile 50%water,the peaks are too close together and are eluted in the range k = 2- 6Should you use a higher or lower concentration of acetonitrile in thenext run?

(b) When you try separating an unknown mixture by normal-phasechromatography with 50%hexane50% methyl t-butyl ether, thepeaks are too close together and are eluted in the range k = 2 - 6Should you use a higher or lower concentration of hexane in thenext run?

The antitumor drug gimatecan is available as nearly pure (S)-enantiomer. Neither pure (R)-enantiomer nor a racemic (equal) mixture of the two enantiomers is available. To measure small quantities of (R)-enantiomer in nearly pure (S)-gimatecan, a preparation was subjected to normal-phase chromatography on each of the enantiomers of a commercial, chiral stationary phase designated (S,S)- and (R,R)-DACH-DNB. Chromatography on the (R,R)-stationary phase gave a slightly asymmetric peak at tr 5 6.10 min with retention factor k 5 1.22. Chromatography on the (S,S)- stationary phase gave a slightly asymmetric peak at tr 5 6.96 min with k 5 1.50. With the (S,S) stationary phase, a small peak with 0.03% of the area of the main peak was observed at 6.10 min.

Chromatography of gimatecan on each enantiomer of a chiral stationary phase. Lower traces have enlarged vertical scale. [Data from E. Badaloni, W. Cabri, A. Ciogli, R. Deias, F. Gasparrini, F. Giorgi, A. Vigevani, and C. Villani, “Combination of HPLC ‘Inverted Chirality Columns Approach’ and MS/MS Detection for Extreme Enantiomeric Excess Determination Even in Absence of Reference Samples.” Anal. Chem. 2007, 79, 6013.]

(a) Explain the appearance of the upper chromatograms. Dashed lines are position markers, not part of the chromatogram. What Problems 709 would the chromatogram of pure (R)-gimatecan look like on the same two stationary phases?

(b) Explain the appearance of the two lower chromatograms and why it can be concluded that the gimatecan contained 0.03% of the (R)-enantiomer. Why is the (R)-enantiomer not observed with the (R,R)-stationary phase?

(c) Find the relative retention (a) for the two enantiomers on the (S,S)-stationary phase.

(d) The column provides N 5 6 800 plates. What would be the resolution between the two equal peaks in a racemic (equal) mixture of (R)- and (S)-gimatecan? If the peaks were symmetric, does this resolution provide baseline separation in which signal returns to baseline before the next peak begins?

Question: Explain how to use a gradient for the first run to decide whether isocratic or gradient elution would be more appropriate.

(a) You wish to use a wide gradient from 5 vol % to 95 vol %B for the first separation of a mixture of small molecules to decide whether to use gradient or isocratic elution. What should be the gradient time, tG,for a 15×0.46-cmcolumn containing 3-μmparticles with a flow of 1.0mL/min

You optimized the gradient separation going from 20vol%to 34 vol% Bin 11.5min at 1.0mLFindk*for this optimized

separation. To scale up to a 15×1.0cmcolumn, what should be the gradient time and the volume flow rate? If the sample load on

the small column was 1mgwhat sample load can be applied to the large column? Verify that k*is unchanged.

a) UHPLC can provide exquisite resolution when run slowly on long columns or rapid separation with reasonaple resolution if short columns are run fast. the drug acetaminophern run on a 50×2.1mmc18UHPLC column has a retention time of 0.63min and a width at half-height of 2.3s.Find the plate number and plate height. How many1.7μm diameter particles places placed dide-by are equal to one theoretical plate?

b) From figure25-3,we expect an optimum plate height of 4μm how many particles placed side-by- side are equal to one theroretical plate? Do you think the column in (a) is being run for maximum resolution or maximum speed?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free