Retention factors for three solutes separated on aC8non-polar stationary phase are listed in the table. Eluent was a 70 : 30 (vol/vol) mixture of 50 mM citrate buffer (adjusted to pH withNH3) plus methanol. Draw the dominant species of each compound at each pH in the table and explain the behavior of the retention factors.

Short Answer

Expert verified

The retention factor is less below pH 7 and more at pH 7.

Step by step solution

01

Explanation for given pH

At all pH values, Acetophenone is neutral and its retention remains unaffected by pH.

In case of Salicylic acid, a neutral molecule HA can be expected. The expected neutral molecule HA might have certain affinity for theC8non-polar stationary phase and the ionA-might have little affinity forC8Salicylic acid is mostly HA below pH 2.97 and above pH is likely showsA-At pH =3 there is 1: 1 ratio mixture of HA andA-that is soberly retained on the non-polar column. At pH5 and 7 , maximum of molecules (more than 99% ) showsA-hence the retention is weak(retention factor is small).

Nicotine in its ionic form is subjected to have less affinity for non-polar stationary phase and the neutral molecule shows affinity to certain extent.

Considering Nicotine as B, the form B is most preferable at abovepH=pK2=7.85BH+is most likely between pH3.15 and7.85

BH22+is most preferable at below 3.15pH

B doesn't become appreciable till pH is approximately equal to 7 , hence the retention factor is less below pH 7 and raise at pH7.

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Most popular questions from this chapter

A bonded stationary phase for the separation of optical isomers has the structure

To resolve the enantiomers of amines, alcohols, or thiols, the compounds are first derivatized with a nitroaromatic group that increases their interaction with the bonded phase and makes them observable with a spectrophotometric detector.

When the mixture is eluted with 20 vol% 2-propanol in hexane, the (R)-enantiomer is eluted before the (S)-enantiomer, with the following chromatographic parameters:

Resolution=Δtrwav=7.7

Relative retention(α)=4.53

k for (R)-isomer =1.35

tm=1.00min

wherewavis the average width of the two Gaussian peaks at their base.

(a) Findt1,t2andwawith units of minutes.

(b) The width of a peak at half-height isrole="math" localid="1663582749865" w1/2(Figure 23-9). If the plate number for cach peak is the same, findw1/2for each peak.

(c) The area of a Gaussian peak is1.064×peakheight×w1/2. Given that the areas under the two bands should be equal, find the relative peak heights(heightR//heightS).

Question: what are the general steps in developing an isocratic separation for reversed-phase chromatography?

Question: How do additives such as trienthylamine reduce tailing of certain solutes?

(a) Make a graph showing retention times of peaks 6, 7, and 8 in Figure 25-12 as a function of %acetonitrile (%B). Predict the retention time of peak 8 at 45% B.

(b) Linear-solvent-strength model: In Figure 25-12, tm = 2.7 min. Compute k for peaks 6, 7, and 8 as a function of %B. Make a graph of log k versus Φ, where Φ= %B/100. Find the equation of a straight line through a suitable linear range for peak 8. The slope is -S and the intercept is log kw. From the line, predict tr for peak 8 at 45% B and compare your answer with (a).

(c) Gradient elution: A linear eluent gradient from 40 to 80% acetonitrile over 30 min is performed on the column in Figure 25-12. Assuming a dwell volume of 0 mL, use your data from (b) to plot the retention factor of peaks 6 and 8 during the gradient. What are the general characteristics of the plot?

(d) Why are the peaks in a gradient separation sharp?

  1. According to equation 25-2if all conditions are constant, but particle size is reduced from3μmto0.7μmby what factor must pressure be increased to maintain constant linear velocity?
  2. If all conditions except pressure are constant, by what factor will linear velocity increase if column pressure is increased by a factor of 10?
  3. With 0.7μmparticles in a 9cm×50column, increasing pressure from 70MPato700MPa decreased analysis time by approximately a factor of 10while increasing plate count from
  4. 12000to4500059Explain why small particles permit faster flow without losing efficiency or,in this case,with improved efficiency.
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