After poisonous melamine and cyanuric acid appeared in milk in China (Box11-3) in 2008, there was a flurry of activity to develop methods to measure these substances. An analytical method for milk is to treat 1volume of milk with 9 volumes of H2O2CH3CN(20:80vol/vol)to precipitate proteins. The mixture is centrifuged for 5minto remove precipitate. The supernatant liquid is filtered through a 0.5-μmfilter and injected into a HILIC liquid chromatography column (TSK gel Amide-stationary phase) and products are measured by mass spectrometry with selected reaction monitoring (Section 22-5). Melamine is measured in positive ion mode with the transitionm/z127→85. Cyanuric acid is measured in negative ion mode with the transition m/212842.

(a) Write the formulas for the four ions and propose structures for all four ions.

(b) Even though milk is a complex substance, only one clean peak is observed for melamine and one for cyanuric acid spiked into milk. Explain why

Short Answer

Expert verified

a)The formulas are

b) There aren't many other species in milk that can produce the same two ions as these two. Melamine and cyanuric acid have just one peak in the mass spectrum as a result.

Step by step solution

01

Definition of chemical formula.

A chemical formula is a technique of expressing the chemical quantities of atoms that make up a certain chemical compound or molecule.

02

Step 2: The formulas for the four ions and propose structures for all four ions.

a)

Melamine is a molecule with a molecular weight of 126 . It decomposes in positive ion mode to generate an -m/z fragment. This implies that melamine H+loses a 42Da. This is most likely related to the loss of CN2H2.

IfCN2H2islost,thentheremainingcationisC2H4H5+.Thestructureforthesamecanbeproposedas,

[Cyanuric acid-H] decomposes to m/z=42.

This is more likely to be a cyanate ionNC-O-.

03

Step 3: Explanation of why only one peak is absorbed for melamine and cyanuric acid in milk.

b)

Melamine is a molecule with a molecular weight of 126 . Through collisionally induced dissociation, it decomposes in positive ion mode to generate an 85-m/zfragment. This implies that melamineH+ loses a 42Da.

role="math" localid="1654933425262" CyanuricacidH-decomposes to m/z=42.

This is more likely to be a cyanate ionN=C-O-

There aren't many organisms in milk that can produce the same two ions. As a result, the mass spectra for melamine and cyanuric acid only shows one peak.

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Most popular questions from this chapter

Retention factors for three solutes separated on aC8non-polar stationary phase are listed in the table. Eluent was a 70 : 30 (vol/vol) mixture of 50 mM citrate buffer (adjusted to pH withNH3) plus methanol. Draw the dominant species of each compound at each pH in the table and explain the behavior of the retention factors.

HPLC peak should generally not have an asymmetry factor, B/A in figure 23-14,outside the range0.9-1.5

  1. Sketch the shape of a peak with an asymmetry of 1.8
  2. What might you do to correct the asymmetry?

If along 15cmHPCL column has a place height of 5.0 what will be the half-width (in seconds) of a peak eluted at 10.0min? if plate height5μm,what will bew1/2?

(a) Make a graph showing retention times of peaks 6, 7, and 8 in Figure 25-12 as a function of %acetonitrile (%B). Predict the retention time of peak 8 at 45% B.

(b) Linear-solvent-strength model: In Figure 25-12, tm = 2.7 min. Compute k for peaks 6, 7, and 8 as a function of %B. Make a graph of log k versus Φ, where Φ= %B/100. Find the equation of a straight line through a suitable linear range for peak 8. The slope is -S and the intercept is log kw. From the line, predict tr for peak 8 at 45% B and compare your answer with (a).

(c) Gradient elution: A linear eluent gradient from 40 to 80% acetonitrile over 30 min is performed on the column in Figure 25-12. Assuming a dwell volume of 0 mL, use your data from (b) to plot the retention factor of peaks 6 and 8 during the gradient. What are the general characteristics of the plot?

(d) Why are the peaks in a gradient separation sharp?

A bonded stationary phase for the separation of optical isomers has the structure

To resolve the enantiomers of amines, alcohols, or thiols, the compounds are first derivatized with a nitroaromatic group that increases their interaction with the bonded phase and makes them observable with a spectrophotometric detector.

When the mixture is eluted with 20 vol% 2-propanol in hexane, the (R)-enantiomer is eluted before the (S)-enantiomer, with the following chromatographic parameters:

Resolution=Δtrwav=7.7

Relative retention(α)=4.53

k for (R)-isomer =1.35

tm=1.00min

wherewavis the average width of the two Gaussian peaks at their base.

(a) Findt1,t2andwawith units of minutes.

(b) The width of a peak at half-height isrole="math" localid="1663582749865" w1/2(Figure 23-9). If the plate number for cach peak is the same, findw1/2for each peak.

(c) The area of a Gaussian peak is1.064×peakheight×w1/2. Given that the areas under the two bands should be equal, find the relative peak heights(heightR//heightS).

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